Sorting letters C programming

Question

I'm trying to make the letters of a matrix sort alphabetically and then be written out in a single string.For instance you type ten words,which are then stored in an array,and every letter has its place in the matrix then,right?But after I've written the words I want to bunch all the letters of all words together and then type all the letters out in alphabetical order.This is what I have so far:

#include <stdio.h>
#include <conio.h>

int main(void){
    int i, j, k, f, n, m; 
    //was trying out various things,that's why I have so many useless ints up there
    char word[10][15],temp;

    for(i=0;i<=9;i++)
    {
        printf("Type in wword number %d: ", i+1);
        gets(word[i]);
    }

    for(k=i-1;k>=0;k--)
    {
        for(m=0;m<k;m++)
            if(word[k][f] > word[m][n])
            {
                temp=word[k][f];
                word[k][f]=word[m][n];
                word[m][n]=temp;
            }
    }
    printf("Letters alphabetically sorted: ");
    for(i=0;i<=9;i++){
        for(j=0;j<=14;j++){
            printf("%d",word[i][j]);
        }
    }
    printf("\n");
    getch();
}

I'm still in the process of learning about matrixes and I've gotten pretty familiar with arrays by now.But the sorting thing is confusing me,this was my attempt but it doesn't work.It lets you write all the words,and then it crashes.

What am I doing wrong here?And how do I correct it?

Wait nevermind,figured it out.Thank you for the comment though. — user956281
– user956281, Commented Sep 21, 2011 at 6:45

evgeny · Accepted Answer · 2011-09-21 06:38:20Z

3

In your code here:

        temp=word[k][f];
        word[k][f]=word[m][n];
        word[m][n]=temp;

the variables n and f are used uninitialised. That will most likely be the cause of the crash.

answered Sep 21, 2011 at 6:38

evgeny

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3 Comments

user956281 Over a year ago

Ok thnx :) Now it doesn't crash.But at the end,instead of the letters it displays some odd row of numbers.Why is that?

evgeny Over a year ago

You want to print out with "%c": that's "character". You're printing "%d", which are numbers.

user956281 Over a year ago

Ok,put it to %c.Now it displays characters though hmmm,I was figuring it would type out letters from the words.Like I type in the words "one,two,three" and it types out: "eeehnoorttw"

Mahesh · Accepted Answer · 2011-09-21 06:38:25Z

1

f,n are uninitialized. It has garbage and is the reason for crashing at this point.

for(k=i-1;k>=0;k--)
{
    for(m=0;m<k;m++)

    if(word[k][f] > word[m][n]) // f,n are uninitialized and are error prone

answered Sep 21, 2011 at 6:38

Mahesh

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1 Comment

user956281 Over a year ago

Thank you for the help,I've fixed the initializing now.And I changed the last %d to a %c.But now it displays characters.I was hoping it would type out letters from the words.Example: I type in the words "one two three" and it types out: "eeehnoorttw".How do I make it so?

sudharsan · Accepted Answer · 2011-09-22 08:11:40Z

0

I think this will work..Please excute and tell me..

void main()    
{

char word[10][15],temp,sorted_word[15];

int i,j,ii,k,l=0;

for(i=0;i<=9;i++)             
{                  
printf("Type in wword number %d: ", i+1);                 
gets(word[i]);            
}


for(i=0;i<=9;i++)

{

for(j=0;word[i][j]!='\0';j++)

{

ii=i;
for(k=j+1;1;k++)
{
if(ii==9 && word[ii][k]=='\0')
break;
if(word[ii][k]=='\0')
{
ii++;
k=0;
}
if(word[i][j]>word[ii][k])
{
temp=word[i][j];
word[i][j]=word[ii][k];
word[ii][k]=temp;
} 
}
sorted_word[l++]=word[i][j];
}

}

sorted_word[l]='\0';

printf("%s",sorted_word);

getch();

}

answered Sep 22, 2011 at 8:11

sudharsan

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Comments

Gouse Shaik · Accepted Answer · 2011-09-21 06:50:02Z

-1

here the

for(i=0;i<=9;i++)
{ printf("type in wword %d: ",i+1);
gets(word[i]); 
}

gets (word[1]);

stores the value from word[1] onwards but where as the character array starts from word[0].

may be this is not the full solution for u problem this issue may help u in solving your doubt.

answered Sep 21, 2011 at 6:50

Gouse Shaik

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