Creating multiple sublists in Python

Question

I have a list J with len(J)=2. I want to create a sublist of each element in J[i] where i=0,1. I present the current and expected output.

J = [[1, 2, 4, 6, 7],[1,4]]
arJ1=[]

for i in range(0,len(J)):
    J1=[J[i]]
    arJ1.append(J1)
    J1=list(arJ1)
print("J1 =",J1)

The current output is

J1 = [[[1, 2, 4, 6, 7], [1, 4]]]

The expected output is

J1 = [[[1], [2], [4], [6], [7]], [[1], [4]]]

[[[j] for j in i] for i in J]

Epsi95
– Epsi95

2023-01-02 06:29:39 +00:00
Commented Jan 2, 2023 at 6:29 — Epsi95
– Epsi95, Commented Jan 2, 2023 at 6:29

Abhishek · Accepted Answer · 2023-01-02 06:22:00Z

1

you can try this,

J = [[1, 2, 4, 6, 7],[1,4]]
new_l = []
for l in J:
    tmp = []
    for k in l:
        tmp.append([k])
    new_l.append(tmp)

print(new_l)

this will give you [[[1], [2], [4], [6], [7]], [[1], [4]]]

answered Jan 2, 2023 at 6:22

Abhishek

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RomanPerekhrest · Accepted Answer · 2023-01-02 06:29:55Z

1

With simple list comprehension:

res = [[[i] for i in sub_l] for sub_l in J]
print(res)

[[[1], [2], [4], [6], [7]], [[1], [4]]]

answered Jan 2, 2023 at 6:29

RomanPerekhrest

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Talha Tayyab · Accepted Answer · 2023-01-02 06:30:53Z

1

You can do in one line with list comprehension:

[[[k] for k in l] for l in J]

answered Jan 2, 2023 at 6:30

Talha Tayyab

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Peddi Santhoshkumar · Accepted Answer · 2023-01-02 06:36:36Z

1

J = [[1, 2, 4, 6, 7],[1,4]]
arJ1 = []

for in_list in J:
    new_list = []
    for x in in_list:
        new_list.append([x])
    arJ1.append(new_list)

print(arJ1)

answered Jan 2, 2023 at 6:36

Peddi Santhoshkumar

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