Thymeleaf results in error when using variable inside an expression

Question

For the provided string in my model, I want to print a "growing" list of substrings. For example, if the given string is Wine, the result should be:

W
Wi
Win
Wine

I've come up with the following construct:

<h1 th:with="len=${#strings.length(name)}" th:each="i : ${#numbers.sequence(1, ${len})}" th:text="${#strings.substring(name, 0, i)}"></h1>

but it doesn't work.

If I change ${#numbers.sequence(1, ${len})} to ${#numbers.sequence(1, 4)} it works. However, this way I'd need to manually change the code whenever my initial string's length changes.

I've tried with messages.msg() alternative, but no luck either.

Error:


An error happened during template parsing (template: "class path resource [templates/name-list.html]")
Caused by: org.attoparser.ParseException: Exception evaluating SpringEL expression: "#numbers.sequence(1, ${len})" (template: "name-list" - line 7, col 53)

What am I doing wrong?

Metroids · Accepted Answer · 2023-01-04 15:41:00Z

1

th:each has a higher attribute precedence than th:with. Since th:each is evaluated first, the len variable is not available here.
In most cases, you should not/cannot nest ${...} expressions. If the len variable was available here, you should have used len instead of ${len}.

.

<h1
  th:each="i : ${#numbers.sequence(1, #strings.length(name))}"
  th:text="${#strings.substring(name, 0, i)}" />

answered Jan 4, 2023 at 15:41

Metroids

20.6k4 gold badges49 silver badges56 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Thymeleaf results in error when using variable inside an expression

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related