Iterating through multiple arguments in a function?

Update: Here's a slightly optimized version by precomputing the 5th power of each number and removing unreachable values of n. (Original version down below)

from itertools import product

def euler(a, b, c, d):
    y = A5[a] + B5[b] + C5[c] + D5[d]
    if y in N:
        n = N.index(y) + 140
        my_dict = {'A1': [], 'A2': [], 'A3': [], 'A4': [], 'Number': []}
        my_dict['A1'].append(a)
        my_dict['A2'].append(b)
        my_dict['A3'].append(c)
        my_dict['A4'].append(d)
        my_dict["Number"].append(n)
        return my_dict

# generate lists of numbers to iterate
A = list(range(20, 41))
B = list(range(80, 101))
C = list(range(100, 121))
D = list(range(120, 141))

# precompute 5th powers of a, b, c, d
A5 = {a: a**5 for a in A}
B5 = {b: b**5 for b in B}
C5 = {c: c**5 for c in C}
D5 = {d: d**5 for d in D}

# precompute 5th powers of n, removing unreachable values
N = [n**5 for n in range(140, 161) if n**5 <= 40**5 + 100**5 + 120**5 + 140**5]

for a, b, c, d in product(A, B, C, D):
    if res:= euler(a, b, c, d):
        print(res)

Original: Here's a simple implementation (thanks to @JonSG, it was product, not combinations!)

from itertools import product

def euler(a,b,c,d):
    my_dict = {'A1':[],'A2':[],'A3':[],'A4':[],'Number': []}
    y = a**5 + b**5 + c**5 + d**5
    for n in range(140,161):
        if n**5 == y:
            my_dict['A1'].append(a)
            my_dict['A2'].append(b)
            my_dict['A3'].append(c)
            my_dict['A4'].append(d)
            my_dict["Number"].append(n)
            return my_dict  
        else:
            pass

A = range(20, 41)
B = range(80, 101)
C = range(100, 121)
D = range(120, 141)

for a, b, c, d in product(A, B, C, D):
    res = euler(a, b, c, d)
    if res:
        print(res)