1

I have an array A. I want to print total number of values in the range [1e-11,1e-7]. But I am getting an error. I present the expected output.

import numpy as np 

A=np.array([ 4.21922009e+002,  4.02356746e+002,  3.96553289e-09,
        3.91811967e-010,  3.88467908e-08,  3.86636300e-010])

B=1e-11<A<1e-07
print(B)

The error is

 in <module>
    B=1e-11<A<1e-07

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

The expected output is

4

2 Answers 2

2

The numpy-way is to refactor the interval condition into two subconditions using the & operator:

a = np.array([ 4.21922009e+002,  4.02356746e+002,  3.96553289e-09,
        3.91811967e-010,  3.88467908e-08,  3.86636300e-010])

mask = (1e-11<a) & (a<1e-07)

# if you care about the values of the filtered array
print(a[mask].size)

# or just
print(np.count_nonzero(mask))
Sign up to request clarification or add additional context in comments.

Comments

1

You can't use your code with numpy array:

B = sum((1e-11<A) & (A<1e-07))
print(B)

# Output
4

It doesn't make sense for Python (and not numpy) to compare 2 scalar values to an array.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.