Selenium Python: How to extract text within a href element

Question

I am looking for a way to extract/print text which is located within a href element.

Snapshot of the HTML:

Code trials:

WebDriverWait(driver, 20).until(EC.visibility_of_element_located(By.XPATH('//div[contains(@class, "style1")]')))
driver.find_element_by_xpath('//div[contains(@class, "style1")]').text

Error massage: TypeError: 'str' object is not callable

Many more trials to locate this "0" without success. The number will change when some open 'tickets' appear in the system.

How this could be done?

KunduK · Accepted Answer · 2023-02-07 10:28:52Z

1

if you print this, it should return the value 0

print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH,'//div[contains(@class, "style1")]/a'))).text)

You need to change this from

driver.find_element_by_xpath('//div[contains(@class, "style1")]').text

to

print(driver.find_element(By.XPATH,'//div[contains(@class, "style1")]/a').text)

You need to import this library.

from selenium.webdriver.common.by import By

edited Feb 7, 2023 at 10:28

answered Feb 7, 2023 at 9:17

KunduK

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4 Comments

Paulina Over a year ago

Thanks. I used your code, but still get this error: "TypeError: 'str' object is not callable"

KunduK Over a year ago

@Paulina, Sorry I mistake. Try now. I have updated the answer.

Paulina Over a year ago

now i get: "TypeError: __init__() takes 2 positional arguments but 3 were given"

KunduK Over a year ago

@Paulina, Just copy exact what I have posted. if you don't want to print this just use this line WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH,'//div[contains(@class, "style1")]/a'))) I am sure you have missed one parenthesis.

undetected Selenium · Accepted Answer · 2023-02-07 13:38:56Z

0

You were close enough. The untill() method accepts a tuple. Hence you see the error:

TypeError: 'str' object is not callable

Moreover the text 0 is within the descendant <a> of the <div>.

Solution

Your effective line of code will be:

Using text attribute:

print(WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, "//div[contains(@class, 'style1')]/a"))).text)

Using get_attribute():

print(WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, "//div[contains(@class, 'style1')]/a"))).get_attribute('textContent'))

Alternative

As an alternative considering thw href attribute of the <a> tag you can use:

print(WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='style1']/a[starts-with(@href, '/scp/endeavour/deviationDetailsPortlet')]"))).text)

edited Feb 7, 2023 at 13:38

answered Feb 7, 2023 at 12:01

undetected Selenium

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2 Comments

Paulina Over a year ago

both lines suggested in 'Solution' shows Syntax error (pointing out s in "style1") - don't know why there. Alternative code give Timeout error.

undetected Selenium Over a year ago

1) both lines suggested in 'Solution' shows Syntax error (pointing out s in "style1"): my bad, corrected the bug. 2) Alternative code give Timeout error": corrected now

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