Ramda filter array of objects based on multiple conditions

Question

I am trying to return an array of keys from a nested array based on two conditions using Ramda:

object has a property delete: false
object does not have property delete

So my array looks something like this:

  const array = [{id: 1, name: "test1"}, {id: 2, name: "test2", delete: true}, {id: 3, name: "test3", delete: false}]

So the result should be [1, 3]

So far I have this statement, which partially works, it returns the ids for the objects that don't have property delete, I am not sure how to check if property had delete: false and return it in the result:

map(
    pipe(
      ifElse(
        has("delete"),
        pipe(propEq("delete", false), prop("id")),
        prop("id")
      )
    ))(array)

Ori Drori · Accepted Answer · 2023-02-08 23:55:18Z

3

Reject all items with delete: true, and then get an array of ids using R.pluck:

const { pipe, reject, prop, pluck } = R

const fn = pipe(
  reject(prop('delete')), // remove all items with delete: true
  pluck('id') // take the ids
)

const array = [{id: 1, name: "test1"}, {id: 2, name: "test2", delete: true}, {id: 3, name: "test3", delete: false}]

const result = fn(array)

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.28.0/ramda.min.js" integrity="sha512-t0vPcE8ynwIFovsylwUuLPIbdhDj6fav2prN9fEu/VYBupsmrmk9x43Hvnt+Mgn2h5YPSJOk7PMo9zIeGedD1A==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>

If you really want to be specific about the conditions, use R.propSatisfies with R.either, and use R.equals to specify the exact values. However, this is pretty redundant in your case:

const { pipe, filter, propSatisfies, either, equals, pluck } = R

const fn = pipe(
  filter(propSatisfies(
    either(equals(false), equals(undefined)),
    'delete'
  )), // remove all items with delete: true
  pluck('id') // take the ids
)

const array = [{id: 1, name: "test1"}, {id: 2, name: "test2", delete: true}, {id: 3, name: "test3", delete: false}]

const result = fn(array)

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.28.0/ramda.min.js" integrity="sha512-t0vPcE8ynwIFovsylwUuLPIbdhDj6fav2prN9fEu/VYBupsmrmk9x43Hvnt+Mgn2h5YPSJOk7PMo9zIeGedD1A==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>

edited Feb 8, 2023 at 23:55

answered Feb 8, 2023 at 23:46

Ori Drori

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3 Comments

mjolk Over a year ago

What if I needed to get an id from group inside the object {id: 1, name: "test1", group: {id: 45}}. I tried path but it return undefined.

Ori Drori Over a year ago

Use map(path(['group', 'id'])) instead of pluck.

mjolk Over a year ago

Yep, just figured it out. Thank you for the help!

Rohìt Jíndal · Accepted Answer · 2023-02-09 07:57:27Z

0

You can simply achieve this by checking for the property with the help of Object.hasOwn() and filtered out with the help of Array.filter() method.

Live Demo :

const array = [{id: 1, name: "test1"}, {id: 2, name: "test2", delete: true}, {id: 3, name: "test3", delete: false}];

const res = array.filter(obj => !Object.hasOwn(obj, 'delete') || !obj.delete).map(({ id }) => id);

console.log(res);

answered Feb 9, 2023 at 7:57

Rohìt Jíndal

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