Variable substitution in bash

Question

I've recently discovered notify-send, which opens up a notification window, so I can do things like:

compile && notify-send "Done!" || notify-send "Failed"

This made me thing that maybe I want to create a variable:

export NS="&& notify-send \"Done!\" || notify-send \"Failed\""

and then I could easily add it to many command lines for which I want notifications:

compile $NS
send-big-file $NS
start-a-heavy-job $NS

etc. But this obviously doesn't work as it is, and I can't seem to be able to come up with the right combination of variable substitutions to make it work... any ideas?

Keith Thompson · Accepted Answer · 2011-09-26 07:57:16Z

6

Write a function that takes the command as an argument (untested):

ns() {
    "$@" && notify-send Done || notify-send Failed
}

ns compile
...

answered Sep 26, 2011 at 7:57

Keith Thompson

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