How to get return value of php function into my jquery script

Question

I a writing a pic upload script. The script moves the picture to a directory and also puts it into a database. I want to return the directory of this script to my Jquery function, and So I can then add it to a <iframe> or whatever. I hope that I am running the script, but I am not sure if that is indeed occurring. To make sure, how do I get the return value of a php function which is called by an $(jquery).Ajax() call?

$.ajax() will pass to your callback all the server-side script outputs. (In PHP, using echo, <?= ?>…) — millimoose
– millimoose, Commented Sep 29, 2011 at 1:21

xdazz · Accepted Answer · 2011-09-29 02:16:49Z

1

I would suggest using google next time and also reading official manuals..

http://api.jquery.com/jQuery.ajax/

good luck!

this is what you are looking for.

$.ajax({
 success: function(data, textStatus, jqXHR){}
});

edited Sep 29, 2011 at 2:16

xdazz

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answered Sep 29, 2011 at 1:18

jancha

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Matt Williamson · Accepted Answer · 2011-09-29 02:55:54Z

1

Just echo the path in the php script and it will show up in the data argument of the ajax callback.

answered Sep 29, 2011 at 2:55

Matt Williamson

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