How to remove duplicate object based on condition from an array of object in javascript

Question

I have an array of object , I want to remove duplicate one based on 'documentTypeId' and 'flag' value. Here in below object I want to remove the object having 'documentTypeId' value is same and flag value is false. I tried but not getting proper filter. Please find the below code.

const test = [{
    "id": 100,
    "documentTypeId": 3,
    "docName": "test",
    "flag": false
  }, {
    "id": 31184688089,
    "documentTypeId": 1,
    "docName": "test2",
    "flag": true
  },
  {
    "documentTypeId": 3,
    "docName": "test3",
    "flag": true,
    "active": true
  }
]
const res = test.filter((value, index, self) =>
  index === self.findIndex((t) => (
    t.documentTypeId === value.documentTypeId && t.flag == false
  ))
)
console.log(res);

why dont you first filter out flag value false and then do the filter+findindex only for documentTypeId? — cmgchess
– cmgchess, Commented May 3, 2023 at 15:34

E_net4 · Accepted Answer · 2023-05-05 10:07:40Z

0

I am not sure what your goal here is. You might be asking the question wrong. I think what you might be looking at is to remove duplicates from an array based on flags documentTypeId and flag with another condition that if there are duplicates you want to prefer the document which has flag=true.

You could try something like arranging all documentTypeIds in an array and sort them with boolean as first element and pick all documentTypeIds first element after the sort. Like below

const filterFn = (arr) => Object.values(
    arr.reduce((acc, cur) => ({
      ...acc,
      [cur.documentTypeId]: [...acc[cur.documentTypeId] || [], cur]
    }), {}))
  .map(i => i.sort(({flag: a}, {flag: b}) => Number(b) - Number(a))[0]);

const test1 = [{
    "id": 100,
    "documentTypeId": 3,
    "docName": "test",
    "flag": false
  }, {
    "id": 31184688089,
    "documentTypeId": 1,
    "docName": "test2",
    "flag": true
  },
  {
    "documentTypeId": 3,
    "docName": "test3",
    "flag": true,
    "active": true
  }
]

const test2 = [{
    "docName": "test1",
    "active": true,
    "documentTypeId": 3,
    "flag": false
  },
  {
    "docName": "test2",
    "active": true,
    "documentTypeId": 1,
    "flag": false
  },
  {
    "docName": "test3",
    "documentTypeId": 5,
    "id": 5,
    "flag": false
  },
  {
    "docName": "test4",
    "active": true,
    "documentTypeId": 16,
    "flag": false
  },
  {
    "docName": "test5",
    "documentTypeId": 16,
    "id": 102,
    "flag": true
  }
]
const filterFn = (arr) => Object.values(
    arr.reduce((acc, cur) => ({
      ...acc,
      [cur.documentTypeId]: [...acc[cur.documentTypeId] || [], cur]
    }), {}))
  .map(i => i.sort(({flag: a}, {flag: b}) => Number(b) - Number(a))[0]);

console.log(filterFn(test1));
console.log(filterFn(test2));

edited May 5, 2023 at 10:07

E_net4

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answered May 3, 2023 at 15:37

Joy Biswas

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3 Comments

UIAPPDEVELOPER Over a year ago

For below array it is not working -

UIAPPDEVELOPER Over a year ago

[{ "docName": "test1", "active": true, "documentTypeId": 3, "flag": false }, { "docName": "test2", "active": true, "documentTypeId": 1, "flag": false }, { "docName": "test3", "documentTypeId": 5, "id": 5, "flag": false }, { "docName": "test4", "active": true, "documentTypeId": 16, "flag": false }, { "docName": "test5", "documentTypeId": 16, "id": 102, "flag": true } ]

Joy Biswas Over a year ago

@UIAPPDEVELOPER check now. hope this helps

Thomas Frank · Accepted Answer · 2023-05-03 15:46:23Z

-1

const data = [
  {
    "id": 100,
    "documentTypeId": 3,
    "docName": "test",
    "flag": false
  }, {
    "id": 31184688089,
    "documentTypeId": 1,
    "docName": "test2",
    "flag": true
  },
  {
    "documentTypeId": 3,
    "docName": "test3",
    "flag": false,
    "active": true
  }
];

let typeMem = [];
let filtered = data.filter(({ flag: f, documentTypeId: d }) => 
  f || (typeMem[d] = (typeMem[d] || 0) + 1) && typeMem[d] < 2);

console.log(filtered);

answered May 3, 2023 at 15:46

Thomas Frank

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