i want to get only not null values count in that array , if i use count() or sizeof it will get the null indexes also .
in my case
i have an array like this Array ( [0] => )
the count is 1 . but i want to get the not null count , inthis case it should be 0 , how can i do this , please help............................
simply use array_filter() without callback
print_r(array_filter($entry));
$count = count(array_filter($array));
array_filter will remove any entries that evaluate to false, such as null, the number 0 and empty strings. If you want only null to be removed, you need:
$count = count(array_filter($array,create_function('$a','return $a !== null;')));
something like...
$count=0;
foreach ($array as $k => $v)
{
if (!empty($v))
{
$count++;
}
}
should do the trick. you could also wrap it in a function like:
function countArray($array)
{
$count=0;
foreach ($array as $k => $v)
{
if (!empty($v))
{
$count++;
}
}
return $count;
}
echo countArray($array);
One option is
echo "Count is ".count(array_filter($array_with_nulls, 'strlen'));
If you don't count empty and nulls values you can do this
echo "Count is ".count(array_filter($array_with_nulls));
In this blog you can see a little more info
http://briancray.com/2009/04/25/remove-null-values-php-arrays/
// contact array
$contact_array = $_POST['arr'];
//remove empty values from array
$result_contact_array = array_filter($contact_array);
NULLor is''(empty string) andFALSEokay to remove as well (basically everythingFALSEin PHP)?