Execute XSLT Transform from Java with parameter

Question

I am executing an XSLT transform from within my java web application with no problems, as follows:

Transformer transformer = TransformerFactory.newInstance().newTransformer(xslSource);
transformer.transform(xmlInput, xmlOutput);

In my XSLT transform I am now adding a call to the document() function to load the response from a RESTful web service:

<!-- do stuff -->
<xsl:variable name="url">
   http://server/service?id=<xsl:value-of select="@id"/>
</xsl:variable>
<xsl:call-template name="doMoreStuff">
   <xsl:with-param name="param1" select="document($url)/foo"/>
</xsl:call-template>

Ok cool, no problem. But now, I want to read the base URL from a utils class in java and pass it in to the stylesheet.

//java
String baseUrl = myUtils.getBaseUrl();

<!-- xslt -->
<xsl:variable name="url">
   <xsl:value-of select="$baseUrl"/>
   <xsl:text>/service?id=</xsl:text>
   <xsl:value-of select="@id"/>
</xsl:variable>

Any suggestion on how to do this? My Java utils class loads the value from a myApp.properties file on the classpath, but I'm not sure I can utilize that from XSLT...

Mads Hansen · Accepted Answer · 2011-10-07 01:50:22Z

7

Declare an xsl:param in your stylesheet, so that the baseUrl value can be passed at invocation time:

<xsl:param name="baseUrl" />

Set the parameter on the Transformer object:

Transformer transformer = TransformerFactory.newInstance().newTransformer(xslSource);
transformer.setParameter('baseUrl', myUtils.getBaseUrl());
transformer.transform(xmlInput, xmlOutput);

If you are using XSLT 2.0, then you may consider using the resolve-uri() function when you are constructing the url variable value:

<xsl:variable name="url" 
              select="resolve-uri(concat('/service?id=', @id), $baseUrl)" />

resolve-uri() can help compensate for trailing slashes, hashtags, and other things in the baseUrl that might otherwise result an invalid URL to be constructed by simply concatenating the $baseUrl with the fragment and @id.

answered Oct 7, 2011 at 1:50

Mads Hansen

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1 Comment

karl Over a year ago

Important to note that <xsl:param> must be declared at the top level of the stylesheet. If you declare it within a template, it will be considered a parameter to the template not to the whole stylesheet.

Clafou · Accepted Answer · 2011-10-06 22:23:21Z

6

Call setParameter on your Transformer instance, with the name and value of your parameter. Then inside your XSLT document declare the parameter using <xsl:param name="yourParamName" /> and you can then use it in your XSLT for example this way: <xsl:value-of select="$yourParamName" />

answered Oct 6, 2011 at 22:23

Clafou

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