Bash Loop Program

Question

This is not a homework by anyway to start with this part of a program I'm working on. what I'm trying to do is to print this shape using bash loops.

********
  ****
   **

This is what I have so far, it will print the shape, but I'm trying to find a way jut to use on echo statement, so for example if I put Var="8" and then decrement var by 2 and print them on the same line. Any help is welcomed thanks

 #!/bin/bash 
         COUNTER="1"
            until [  $COUNTER -lt 1 ]; do
echo  "**********"
echo  " ******** "
echo  "  ******  "
echo  "   ****   "
echo  "    **    "

              let COUNTER-=1
        done

Charlie Martin · Accepted Answer · 2011-10-07 22:12:04Z

1

You can do a loop with arithmetic in bash using the $((expr)) notation, much as you would in any other programming language. So, write a function like

function printNx {
   N=$1
   X=$2
   count=0
   while $(($count++ < $N))
   do
      echo -n $X
   done
   echo ""
}

(Don't depend on the syntax until I've checked it. I program in about a zillion scripting languaes and get them confused.)

Update

Almost had it:

bash $ cat foo.bash
function printNx {
   N=$1
   X=$2
   count=0
   while [ $((count ++ )) -lt $N ]
   do
      echo -n "$X"
   done
   echo ""
}

printNx 5 '*'
bash $ bash foo.bash
*****
bash $

edited Oct 7, 2011 at 22:12

answered Oct 7, 2011 at 21:11

Charlie Martin

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1 Comment

Ahmad Nadaf Over a year ago

Thanks Charlie I will try it and let you know

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