PHP anonymous function in arrays, what's the syntax?

Question

Can i define anonymous functions as array value? This is not working:

   $m = array(
        0 => array('condition' => function($v) { return intval($v)}),
        3 => array('condition' => function($v) { return trim($v) > 0})
    );

Kerrek SB · Accepted Answer · 2011-10-08 21:02:20Z

4

In PHP, every statement has to be terminated by a semicolon. Try this:

$m = array(
           0 => array('condition' => function($v) { return intval($v);   } ),
           3 => array('condition' => function($v) { return trim($v) > 0; } )
           );

See the documentation for details.

answered Oct 8, 2011 at 21:02

Kerrek SB

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Alessandro Desantis · Accepted Answer · 2011-10-08 21:05:16Z

2

Try this:

$m = array(
    0 => array('condition' => function($v) { return intval($v); }),
    3 => array('condition' => function($v) { return trim($v) > 0; }),
);

You forgot the ;.

answered Oct 8, 2011 at 21:05

Alessandro Desantis

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