Django simple ModelForm not showing on page (I'm using class based-views), what could be the problem?

Question

I'm trying to build a form to use it as a filter for my project search page, but the {{form}} shows nothing. Here is how everything is set up:

The model I'm trying to use from models.py

class Exemplar(models.Model):
    class Meta:
        verbose_name_plural = 'Exemplares'
    tipoDeExemplar = models.ForeignKey(TipoDeExemplar, on_delete=models.SET_NULL, blank=True, null=True, verbose_name="Tipo De Exemplar")
    numeroDeRegistro = models.CharField(max_length=255, verbose_name="Número Do Registro")
    especie = models.ForeignKey(Especie, on_delete=models.CASCADE, null=True)
    dataDoRegistro = models.DateField(blank=True, null=True, verbose_name="Data Do Registro")
    estadoDoExemplar = models.CharField(blank=True, null=True, max_length=255, verbose_name="Estado do Exemplar")
    tipoDeMaterial = models.CharField(blank=True, null=True, max_length=255, verbose_name="Tipo De Material")
    procedencia = models.CharField(blank=True, null=True, max_length=255, verbose_name="Procedência")
    remetente = models.CharField(blank=True, null=True, max_length=255, verbose_name="Remetente")
    armario = models.CharField(blank=True, null=True, max_length=255, verbose_name="Armário")
    gaveta = models.CharField(blank=True, null=True, max_length=255, verbose_name="Gaveta")
    complemento = models.CharField(blank=True, null=True, max_length=255, verbose_name="Complemento")
    amostraDeOrigem = models.CharFie
    fotoDoExemplar = models.ImageField(null=True, blank=True, upload_to='imagens/', verbose_name="Foto Do Exemplar")
    slug = models.SlugField(max_length=255, unique=True)

    def __str__(self):
        return self.numeroDeRegistro

My forms.py file (very short)

from django.forms import ModelForm
from acervo.models import Exemplar

class ExemplarForm(ModelForm):
    class Meta:
        model = Exemplar
        fields = '__all__'

My view on views.py (seems to be working since I can open the page)

class BuscaView(ListView):
    model = Exemplar
    template_name = 'busca.html'
    form_class = ExemplarForm

Piece of the HTML template where I try to use the Django ModelForm

<form action="" method="post">
    {% csrf_token %}
    {{ form }}
    <input type="submit" value="Create" />
</form>

From what I've researched in other post and on YouTube tutorials, everything seems to be ok, but only the button shows up. What could be the problem?

ListView does not handles form by default but you can pass the form by overriding get_context_data — Ankit Tiwari
– Ankit Tiwari, Commented Oct 6, 2023 at 6:16

Hosseink9 · Accepted Answer · 2023-10-06 06:11:40Z

0

I think at first you need write {% block content %} in the line 1 or 2 of your code and in the end you should close it with {% endblock %} in the down of your code

And you should write your url view in the action in tag; <form action="{% url 'app_name:url_name' %}">

url_name:

`urlpatterns = [
    path('url', your_view, name='url_name'),
]`

answered Oct 6, 2023 at 6:11

Hosseink9

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