how to convert XML to JSON in java?

Question

How to convert XML to JSON in java servlet.

    <?xml><SOAP-ENV:Envelope xmlns:xsd= "http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:HNS="http://tempuri.org/" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"><SOAP-ENV:Header><HNS:ROClientID SOAP-ENV:mustUnderstand="0">{6C9A8E69-2018-4090-8FA7-DEB98300E102}</HNS:ROClientID></SOAP-ENV:Header><SOAP-ENV:Body SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ro="http://tempuri.org/"><NS1:GetStationListResponse xmlns:NS1="urn:WOOSServices-WOrbitService"><Stations xsi:type="xsd:string"></Stations><Result xsi:type="xsd:string">{
    "MOColmns": [
        {
            "MOTitle": "Description"
        },
        {
            "MOTitle": "station_name"
        },
        {
            "MOTitle": "StationID"
        },
        {
            "MOTitle": "StationINT"
        }
    ]
}</Result></NS1:GetStationListResponse></SOAP-ENV:Body></SOAP-ENV:Envelope>";
            String xml = "<xx yy='nn'><mm>zzz</mm></xx>";

            JSONArray json = (JSONArray) XMLSerializer.read(xml);  
            System.out.println( json );

please help me.

Any reason why the answer is not accepted? :-)

German Latorre
– German Latorre

2013-01-29 21:00:54 +00:00
Commented Jan 29, 2013 at 21:00 — German Latorre
– German Latorre, Commented Jan 29, 2013 at 21:00

German Latorre · Accepted Answer · 2011-11-14 10:11:20Z

10

You can grab a set of Java classes to handle JSON at http://json.org/java/

There you can find the XML and JSONObject classes, among others. This code could work for you:

public String XMLtoJSON(String xml) {
    JSONObject jsonObj = XML.toJSONObject(xml);
    String json = jsonObj.toString();
    return json;
}

edited Nov 14, 2011 at 10:11

answered Oct 11, 2011 at 11:30

German Latorre

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4 Comments

ultrageek Over a year ago

In @antur123's answer, I believe all instances of "string" should be "String", in which case that code should work.

Joe M Over a year ago

@selladurai Any reason this is not selected as the answer?

German Latorre Over a year ago

Excellent observation, @RajeevM, :-)

amity Over a year ago

Hi antur123, I can't able to handle XML.toJSONObject(xml) because i can able to resolve XML, how can i resolve this? please help me.

user1515918 · Accepted Answer · 2013-04-01 17:03:01Z

0

You need to import org.json.XML in your class to resolve XML. Or Put org.json.XML to your classpath.

answered Apr 1, 2013 at 17:03

user1515918

212 bronze badges

Comments

Valentyn Kolesnikov · Accepted Answer · 2022-01-30 21:07:16Z

0

Underscore-java can convert xml to json.

import com.github.underscore.U;

String xml = "<xx yy=\"nn\"><mm>zzz</mm></xx>";

String json = U.xmlToJson(xml);  
System.out.println(json);

edited Jan 30, 2022 at 21:07

answered Jan 3, 2021 at 15:39

Valentyn Kolesnikov

2,1251 gold badge24 silver badges33 bronze badges

Comments

SAM · Accepted Answer · 2024-08-26 00:47:01Z

0

I know this is an old thread. Just wanted to share that I have come up with a generic Java-based XML-to-JSON converter which is able to convert any given XML to a desired JSON. Here is the link: https://github.com/mohapatra-sambit/xml-to-json-converter

Hope this helps!!!

answered Aug 26, 2024 at 0:47

SAM

111 silver badge2 bronze badges

1 Comment

Abra Over a year ago

Maybe you could edit your answer and post code that shows how to use your converter to convert the sample XML in the posted question?

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