How to define a string with values from a defined list in SCHEME

Question

Please help me to do define a string like this..

I have a list which has the values (define temp-list (list '398 '150 '1.15 '2875 '-900 '1565 '800 '230 '200 '0 '0 '0))

I Should declare this as.. (define b "398 150 1.15 2875 -900 1565 800 230 200 0 0 0")

How can i do this in scheme?

Looks like homework... if so, be sure to cite the helpful fellow who provided you with the answer! — John Clements
– John Clements, Commented Oct 13, 2011 at 7:24

C. K. Young · Accepted Answer · 2011-10-13 07:21:08Z

2

If you have SRFI 13 loaded, you can use string-join like so:

(define b (string-join (map number->string temp-list)))

answered Oct 13, 2011 at 7:21

C. K. Young

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Bill the Lizard · Accepted Answer · 2011-11-14 02:47:59Z

1

See http://codepad.org/8DH8mCTQ:

(define temp-list (list '398 '150 '1.15 '2875 '-900 '1565 '800 '230 '200 '0 '0 '0))

(define b
    (let loop ((xs temp-list) (zs '()))
      (if (null? (cdr xs))
          (apply string-append (reverse (cons (number->string (car xs)) zs)))
          (loop (cdr xs) (cons " " (cons (number->string (car xs)) zs))))))

(write b)

edited Nov 14, 2011 at 2:47

Bill the Lizard

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answered Oct 13, 2011 at 11:34

user448810

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