Detect PHP image submit button click

Question

Have a php form with an image for the submit button. Am trying to determine whether the submit button has been clicked when the page posts back. Have tried

$testForm = 'fail';
if (isset($_POST['btnSubmit'])) {
    $testForm = 'Submit clicked';
}

button code:

<input name="btnSubmit" value="Submit" style="float: right;" type="image" src="images/submit.gif" width="181" height="43" alt="Submit Form" />

However it doesn't seem to be working. Have tried getting values of other input elements on the page and they work fine. Is there some special method for dealing with image buttons?

Try to print_r( $_POST ) so you'll see everything that's submitted. — JJJ
– JJJ, Commented Oct 14, 2011 at 8:38
See php.net/manual/en/language.variables.external.php under "IMAGE BUTTONS" and php.net/manual/en/faq.html.php#faq.html.form-image — mario
– mario, Commented Oct 14, 2011 at 8:42

oezi · Accepted Answer · 2011-10-14 08:39:23Z

7

a image-button submits the clicked coordinates as [name]_x and [name]_y on submit instead of its value as [name] (some browsers also do this, but not all, while the coordinates are set from every browser). that said, you could simply check:

if (isset($_POST['btnSubmit_x'])) {

answered Oct 14, 2011 at 8:39

oezi

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2 Comments

mario Over a year ago

It's actually btnSubmit.x and .y - but PHP transforms it into an underscore.

oezi Over a year ago

thanks for the additional info, mario - i just cared about how this can be handeled inside of the php-script.

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