Javascript dynamic hash creation

Question

here is my working function. How to create dataObject dynamically? (let's assume that I know how many columns I have) I tried dynamically create variables 'value+i' with eval function, but with no success.

    function parseCSV(rows){
        dataProvider = [];
        for (var i = 0; i < rows.length; i++){
            if (rows[i]) {                   
                var column = rows[i].split(","); 
                var date = someFunction(column[0]);
                var value1 = column[1];
                var value2 = column[2];
                var dataObject = {date:date, value1:value1, value2:value2};
                dataProvider.push(dataObject);
            }
        }
    }

thank U

I don't understand what you want it to do that it isn't already doing. You end up with an array of objects, each one corresponding to a row; how is that not good enough? Did you want an object holding objects instead? Could you show us the code you tried that didn't work? — Karl Knechtel
– Karl Knechtel, Commented Oct 21, 2011 at 21:50
Do you mean for dataProvider to be a global variable rather than declaring it locally and then returning it from the parseCSV() function? — jfriend00
– jfriend00, Commented Oct 21, 2011 at 22:05

mephisto123 · Accepted Answer · 2011-10-21 21:48:52Z

4

There are few approaches.

First:

var hash = new object();
hash["date"] = date;
hash["value1"] = value1;
hash["value2"] = value2;

Second:

var hash = {};
hash["date"] = date;
hash["value1"] = value1;
hash["value2"] = value2;

Third:

var hash = {"date" : date, "value1" : value1, "value2" : value2};

answered Oct 21, 2011 at 21:48

mephisto123

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2 Comments

Bart Over a year ago

And don't forget simply hash.myNewValue = 42;

mephisto123 Over a year ago

hash should be created anyway before. using variables before declaring em is a bad practice.

Zack Bloom · Accepted Answer · 2011-10-21 21:53:32Z

0

If you don't know how many columns you have, but want to create an object full of valueX's:

var date = someFunction(column[0]);
var dataObject = {date: date};

for (var i=1; i < column.length; i++){
    dataObject['value' + i] = column[i];
}

Rather than using value1, ... you should try to use more descriptive names, if possible.

answered Oct 21, 2011 at 21:53

Zack Bloom

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