Is there a way to replace a float element in an array with a string element in python? [closed]

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I have two arrays in my code. One is a grid that is just filled with zero and the other is an array of characters with positions they need to be placed in on the grid. I included an image with my position array on the top and the grid on the bottom.

I'm trying to fill in the grid given the characters positions. For example, I would write this

grid[0][0] = pos[0][0]

To place the character * on the top left. However it's giving me a value error

ValueError: could not convert string to float: '*'

I assume this is because the grid element is a float integer the position elements is a string. Is there any way around this?

You would need to specify what language you're using! In some languages, having mixed types in an array is trivial, in others it is fundamentally impossible. — jasonharper
– jasonharper, Commented Aug 3, 2024 at 2:45
My fault, it's python, I updated the tag and the question title. — Boltu
– Boltu, Commented Aug 3, 2024 at 3:20
Please edit the post with text not images, and show a minimal reproducible example exhibiting the error. — Mark Tolonen
– Mark Tolonen, Commented Aug 3, 2024 at 3:32
This looks like a numpy array. All the elements have to be the same type. — Barmar
– Barmar, Commented Aug 3, 2024 at 4:13

Hermann12 · Accepted Answer · 2024-08-03 07:36:37Z

-1

Maybe there is a better way, I tried this:

import numpy as np

l =[['*',0,2],['C',1,0]]

arr = np.array(l, dtype=object)

alist = [(ord(i[0]), i[1], i[2]) for i in arr]
arr_f = np.array(alist, dtype=float).reshape((1,6))
print(arr_f)

slist = [(chr(int(i[0])), int(i[1]), int(i[2]), chr(int(i[3])), int(i[4]), int(i[5])) for i in arr_f]
print(np.array(slist, dtype=object).reshape((2,3)))

Output:

[[42.  0.  2. 67.  1.  0.]]
[['*' 0 2]
 ['C' 1 0]]

answered Aug 3, 2024 at 7:36

Hermann12

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