api integration php curl

Question

I am trying to integrate an API, and in the API integration instructions it shows the following:

GET /offers.json or /offers.xml
Headers: API-KEY={your_key}, API-LOGIN={your_login}

CURL Example:

curl https://api.thewebsite.com/v1/offers.json -H 'API-KEY:
1a2b3c4d5e6f7g8h9i' -H 'API-LOGIN: 1a2b3c4d5e6f7g8h9i'

I've tried using the cURL code below without success. As for the GET method, I'm not sure how to pass the API KEY & API LOGIN as headers.

$header = array('Content-Type: application/xml', 'API-KEY=1a2b3c4d5e6f7g8h9i', 'API-LOGIN=1a2b3c4d5e6f7g8h9i');
$url = "https://api.thewebsite.com/v1/offers.xml";

$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
$xml = curl_exec($curl);
curl_close($curl);

print $xml;

I was getting a Invalid API key error, which would be due to the use of = rather than : as Kaivosukeltaja pointed out. — spiderling
– spiderling, Commented Oct 25, 2011 at 19:04

Kaivosukeltaja · Accepted Answer · 2011-10-25 18:32:40Z

5

HTTP headers need to be specified using a colon as the separator between the key and the value, not an equal sign. Try this:

$header = array('Content-Type: application/xml', 'API-KEY: 1a2b3c4d5e6f7g8h9i', 'API-LOGIN: 1a2b3c4d5e6f7g8h9i');

answered Oct 25, 2011 at 18:32

Kaivosukeltaja

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2 Comments

spiderling Over a year ago

(doh) I had used the = trying something else and forgot to change it. Thanks!

spiderling Over a year ago

I've been trying to only print the details of the first offer returned. However the entire XML is displayed. Even if I remove all print calls.

## begin snip ## <?xml version="1.0" encoding="UTF-8"?>   <offers type="array">     <offer>       <end-date type="datetime">2011-09-22T23:59:59Z</end-date>       <details>First offer details here</details>       <faq nil="true"></faq>       <value type="float">495.0</value> ## end snip ##  print $xml->offer[0]->details

aporat · Accepted Answer · 2011-10-25 18:44:18Z

0

You can get some debug information from curl, and see exactly what doesn't work for you:

print "<pre>\n";
print_r(curl_getinfo($curl));  // get error info
echo "\n\ncURL error number:" .curl_errno($curl); // print error info
echo "\n\ncURL error:" . curl_error($ch); 
print "</pre>\n";
curl_close($curl); // close curl session

Make sure to call it before you close and terminate the curl object

answered Oct 25, 2011 at 18:44

aporat

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1 Comment

spiderling Over a year ago

Thanks. I'll keep it handy for the future.

Tushar Walzade · Accepted Answer · 2019-02-28 07:43:07Z

0

Try the following -

print "<pre>\n";
print_r(curl_getinfo($curl));  // get error info
echo "\n\ncURL error number:" .curl_errno($curl); // print error info
echo "\n\ncURL error:" . curl_error($ch); 
print "</pre>\n";
curl_close($curl);

edited Feb 28, 2019 at 7:43

Tushar Walzade

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answered Feb 28, 2019 at 7:32

kjkh

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