I have this regex [a-zA-Z]\d\d\\$\d\d-\d\d\d\d and my value is A11$12-9190. But it is not matching. Any clues?
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That regex is not valid.Hovercraft Full Of Eels– Hovercraft Full Of Eels2011-10-27 16:00:44 +00:00Commented Oct 27, 2011 at 16:00
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What's the actual Java string you're using?millimoose– millimoose2011-10-27 16:01:40 +00:00Commented Oct 27, 2011 at 16:01
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You are escaping \ before the $ thus reaching the end of the string yet you are searching for more digits afterwards. Not possible.FailedDev– FailedDev2011-10-27 16:03:30 +00:00Commented Oct 27, 2011 at 16:03
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4 Answers
Each backslash \ have to be escaped by an extra backslash, \\, in java patterns. Note that your backslash in front of the dollar sign is already escaped.
The resulting regex would be:
[a-zA-Z]\\d\\d\\$\\d\\d-\\d\\d\\d\\d
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Basically what's happening is that Java assumes your \d is an escape character for the String, you'll need to transform it into \\d - the first \ to escape the second \ that escapes the d for the regex!
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Your regex is not valid. e.g.,
String test = "A11$12-9190";
String regex = "[a-zA-Z]\\d\\d\\$\\d\\d-\\d\\d\\d\\d";
System.out.println(test.matches(regex));
answered Oct 27, 2011 at 16:01
Hovercraft Full Of Eels
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Are you escaping all the \? If you have a string, you'll have to do "\\d".
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