XHTML to XML XSLT conversion

Question

I am doing a very simple xslt to convert a html page to a xml file.

But it appears to me that the starting point is not that straightforward to me.My first goal is to convert a <html> tag into a <topic> tag.

I did the following xslt:

 <xsl:template match="@*|node()">
   <xsl:copy>
    <xsl:apply-templates select="@*|node()"/> 
  </xsl:copy>  
 </xsl:template>

 <xsl:template match="/">
   <xsl:apply-templates/>
 </xsl:template>

 <xsl:template match="html">
  <topic>
    <xsl:text> Conversion Test</xsl:text>
  </topic>
 </xsl:template>

However, now after I run this xslt, the result xml is purely of the same content of the original html page, it seems that the third template match that I wrote (to match the <html> tag) never gets hit.

The source html looks like:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
 <html xmlns="http://www.w3.org/1999/xhtml">
   <head>..</head>
   <body>...</body>
 </html>

Could experts help me a little here?

Can you give an example of your html? (especially any namespaces like xmlns="http://www.w3.org/1999/xhtml") — Daniel Haley
– Daniel Haley, Commented Oct 27, 2011 at 18:24

Daniel Haley · Accepted Answer · 2011-11-08 17:12:14Z

5

XSLT 1.0:

Try adding xmlns:x="http://www.w3.org/1999/xhtml" to your xsl:stylesheet and changing your match to match="x:html". (Note: you don't have to use "x"; you can choose anything you want.)

XSLT 2.0:

Either use the above method or replace the namespace prefix in your match(es) to "*" (match="*:html"). You could also add xpath-default-namespace="http://www.w3.org/1999/xhtml" to the xsl:stylesheet.

edited Nov 8, 2011 at 17:12

answered Oct 27, 2011 at 18:33

Daniel Haley

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3 Comments

Kevin Over a year ago

thank you, it worked! Yes, the html is actually xhtml and I am using XSLT1.0, after put in your suggested namespace, worked great:)

Kevin Over a year ago

I updated the title to reflect the nature of the source document too.

Daniel Haley Over a year ago

@Kevin - You're very welcome. Also, if you don't want the namespace in your XML output, add exclude-result-prefixes="#all" to xsl:stylesheet. (Note: you can replace #all with x to exclude x specifically.

Ludovic Kuty · Accepted Answer · 2011-10-27 18:28:27Z

0

You may want to try to remove the first template or make it more specific than matching every node with node().

answered Oct 27, 2011 at 18:28

Ludovic Kuty

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3 Comments

Daniel Haley Over a year ago

Are you saying remove the identity transform?

Kevin Over a year ago

@lkuty, I did try removing the first template. Now the resulting xml is simply a big node of text without any markup. It contains all the text from the original html page.

Ludovic Kuty Over a year ago

I was wrong. I thought the first rule could be chosen insted of the third but in fact the default priority for a match pattern with an element is greater than node() and thus it could not be the problem. I just didn't think about NS.

Rob · Accepted Answer · 2011-10-27 18:41:40Z

0

The purpose of XSLT is to transform XML documents into other XML documents. HTML is not a XML document. While XHTML is XML, it is actually HTML reformulated so I'm just not sure what you want to do is easy or possible with XSLT.

answered Oct 27, 2011 at 18:41

Rob

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1 Comment

Rob Over a year ago

So NOW you update the title :). That reflects my problem with this.

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