I have this hex value 93 which in decimal value should be 147. Since this number is less than 255, it is representable in a byte.
In java I did this
System.out.println((new Integer(1)).byteValue()); //prints 1
System.out.println((new Integer(147)).byteValue()); //prints -109!!! WHY?
What am I not understanding? with integer of 147 instead of printing 147 it prints -109...
A byte in Java is signed, therefore it represents the values in the range of -128 to 127, as opposed to the unsigned alternative in other languages in the range of 0 to 255. All of Java's integer types are signed, excluding char since since it's used to hold 16-bit Unicode values from 0 to 65535.
The value 147 stored as a byte is represented in binary as:
10010011
Since according to the Oracle docs a byte is: "an 8-bit signed two's complement integer", the signed value becomes:
= -2^7 + 2^4 + 2^1 + 2^0
= -128 + 16 + 2 + 1
= -109
Because byte is in the range -128:127 (see here). When you call byteValue() you can't get anything out of that range, so it overflows (and starts from the lowest value)
char is an unsigned short