Reverse an array and finding the valid value

Question

I have an reversed array

 NSArray *reversedArray = [[arr reverseObjectEnumerator] allObjects];

It contains following value

Reversed Array: ( 0, 0, "0.1702998", "0.4936719", 0, "0.1861508", )

So the value which are comming are dynamic, So i want the first non zero value from this array.

How can i do this?

Do both 0 and "0.0000000" count as zero?

Mark Byers
– Mark Byers

2011-11-07 17:11:04 +00:00
Commented Nov 7, 2011 at 17:11 — Mark Byers
– Mark Byers, Commented Nov 7, 2011 at 17:11
Yes i do not need both of value.

user930195
– user930195

2011-11-07 17:12:12 +00:00
Commented Nov 7, 2011 at 17:12 — user930195
– user930195, Commented Nov 7, 2011 at 17:12

Stefan Arentz · Accepted Answer · 2011-11-07 17:12:34Z

1

double firstNonZeroValue = 0.0;
for (NSString* stringValue in [array reverseObjectEnumerator]) {
    double value = [stringValue doubleValue];
    if (value != 0.0) {
        firstNonZeroValue = value;
        break;
    }
}

if (firstNonZeroValue != 0.0) {
    ... yay found a non zero value ...
}

answered Nov 7, 2011 at 17:12

Stefan Arentz

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