Having this text:
http://img.oo.com.au/prod/CRWWBGFWG/1t44.jpg
And other texts like this where the last 1 can be any other number and the last 44 can be any other number as well, I need a regex that will match /1t44.jpg.
Everything I've tried so far (/.+?\.([^\.]+)$) matches from the first slash (//img.oo.com.au/prod/CRWWBGFWG/1t44.jpg).
I'm using JavaScript, so whatever works on RegexPal should do.
Here's a simple Regex that will match everything after the last /:
/[^/]*$
If you want to match a filename with a very specific file extenstion, you can use something like this:
/\/\dt\d\d\.jpg$/
This matches:
Or, if you really just want the filename (whatever is after the last slash with any file extension), then you can use this:
/\/[^\/]+$/
This matches:
In your sample string of http://img.oo.com.au/prod/CRWWBGFWG/1t44.jpg, both of these will match /1t44.jpg. The first is obviously much more restrictive since it requires a specific format of the filename. The second matches any filename.
Other choices. In node.js development, you can use the path module and use path.parse() to break a path up into all of its various components.
And, there are various libraries written for the browser that will break up a path into its components too.
As Johnsyweb says, a regular express isn't really needed here. AFAIK the fastest way to do this is with lastIndexOf and substr.
str.substr(str.lastIndexOf('/'));
Of course you don't have to use a regular expression to split a string and pop the last part:
var str="http://img.oo.com.au/prod/CRWWBGFWG/1t44.jpg";
var parts = str.split("/");
document.write(parts.pop() + "<br />");
Based on answer of Scott, try this: (JavaScript)
var url = "http://img.oo.com.au/prod/CRWWBGFWG/1t44.jpg";
var path = url.replace(/(.*)([\\\/][^\\\/]*$)/, "$1" );
var lastElement = url.replace(/(.*)([\\\/][^\\\/]*$)/, "$2" );
This can be also matched for Windows/Nix file path, to extract file name or file path :
c:\Program Files\test.js => c:\Program Files
c:\Program Files\test.js => \test.js
This is for Java on a Linux machine. It grabs the last part of a file path, so that it can be used for making a file lock.
// String to be scanned to find the pattern.
String pattern = ".*?([^/.]+)*$";
// Create a Pattern object
Pattern r = Pattern.compile(pattern);
// Now create matcher object.
Matcher match = r.matcher("/usr/local/java/bin/keystore");
/**
* Now you have two matches
* #0 /usr/local/java/bin/keystore
* #1 keystore
*/
String fileLock = "";
if (match.find()) {
fileLock = match.group(1) + ".lock";
}
A little different than the original question, I know. But I hope this helps others who were stuck with the same problem I had.
