Python Interpreter in Emacs repeats lines

Question

What is happening:

>>> 2 * 10
2 * 10
20
>>>

What I want to happen:

>>> 2 * 10
20
>>>

Does anyone know why the command is printed out before being executed and how to stop it from doing that? I can't find any documentation about this. I'm using Emacs 23 on Mac OS X with Python 2.7.

How are you starting the Python process? run-python, python-shell? — harto
– harto, Commented Nov 9, 2011 at 6:06
Another way is to start ansi-term and then ipython inside it. — Maxim Egorushkin
– Maxim Egorushkin, Commented Nov 9, 2011 at 8:31
Well, I didn't know about ansi-term. I've been using M-x shell so thanks for that. — methodmain
– methodmain, Commented Nov 9, 2011 at 17:19

Eric · Accepted Answer · 2011-11-20 01:24:14Z

12

I don't use python, but I would guess that the python feature you are using has set the variable comint-process-echoes incorrectly. Whatever the value in your buffer is, just reverse the boolean value.

Comint is a support library in Emacs for running inferior processes in Emacs. It interacts with the prompts, and the python shell (or M-x shell) needs to be told about the echo feature.

In your shell buffer with the problem, do:

M-: (setq comint-process-echoes t)  ;; or nil

answered Nov 20, 2011 at 1:24

Eric

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3 Comments

alexplanation Over a year ago

This works for me, too! I wonder if you can help with my question which regards running this in a hook every time python starts up?

Nithin Varghese Over a year ago

@Eric I am using Elpy on Emacs in ubuntu I do have the same problem but this solution is not working.Can help me out

Nithin Varghese Over a year ago

I have found solution by setting the variable elpy-shell-echo-input to nil

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