Javascript multidimentional array sorting by numerical order

Question

I have a two dimensional array that I need to sort numerically. Here is a sample of the array:

I need to order numerically by the [0] values. The values are stored as strings. I have figured how to sort arrays alphabetically and numerically but I can't figure out how to order this array because of the occasional A and B.

Do I understand it right, the array is like this: [ [3, 320], ["55B", 250], 26, 100] ] and not [ [3, "55B", 26], [320, 250, 100] ] ? — Yogu
– Yogu, Commented Nov 9, 2011 at 19:30
Could you maybe describe more specifically how you want the values sorted? It all seems a little arbitrary right now. What are the constraints? In other words, will letters ALWAYS occur in the third position from the left? Stuff like that. — Doug Stephen
– Doug Stephen, Commented Nov 9, 2011 at 19:31
As I understand, he know how to sort, but he dont know how to sort numbers with 'A' and 'B' at the end... — Adam Jurczyk
– Adam Jurczyk, Commented Nov 9, 2011 at 19:37

Zack Bloom · Accepted Answer · 2011-11-09 19:30:57Z

4

The parseInt method will ignore any string characters after the number, removing the A's and B's.

arr.sort(function(rowA, rowB){
    var a = parseInt(rowA[0], 10);
    var b = parseInt(rowB[0], 10);

    if (a > b)
        return 1;
    else if (a < b)
        return -1;
    return 0;
});

answered Nov 9, 2011 at 19:30

Zack Bloom

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1 Comment

ErikE Over a year ago

arr.sort(function (a, b) { return parseInt(a[0], 10) - parseInt(b[0], 10); });

Adam Jurczyk · Accepted Answer · 2011-11-09 19:57:14Z

0

Just for note - if this A and B has nothing to do with sort, than go with parseInt as Zack posted.

But if it should be used in sort, you can go with something like this:

arr.sort(function(l,r){
  var vl = l[0].split(/(\d+)(\D*)/),
      vr = r[0].split(/(\d+)(\D*)/);

  vl[1] = parseInt(vl[1]);
  vr[1] = parseInt(vr[1]);

  if(vl[1] < vr[1]){
    return -1;
  }else if(vl[1] === vr[1]){
      if(vl[2] < vr[2]) return -1;
      else if(vl[2] === vr[2]) return 0;
      else return 1;
  }else{
      return 1;
  }
});

answered Nov 9, 2011 at 19:57

Adam Jurczyk

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