Python two lists finding index value

Question

listEx = ['cat *(select: "Brown")*', 'dog', 'turtle', 'apple']
listEx2 = ['hampter',' bird', 'monkey', 'banana', 'cat']

for j in listEx2:
    for i in listEx:
        if j in i:
            print listEx.index(j)

What I am trying to accomplish is search the items in listEx2 in listEx. If the item from listEx2 is found in listEx, I would like to know how to print the index value of the item found from listEX2 in listEx. Thanks!

Do you want 'cat' to be found because it is contained within 'cat *(select: "Brown")*'? — Mark Byers
– Mark Byers, Commented Nov 13, 2011 at 21:53
What should happen if there are multiple items in listEx containing the string "cat"? Do you want the index of all of them? — Mark Byers
– Mark Byers, Commented Nov 13, 2011 at 21:59

Tim Pietzcker · Accepted Answer · 2011-11-13 21:55:15Z

4

Just use enumerate:

listEx = ['cat *(select: "Brown")*', 'dog', 'turtle', 'apple']
listEx2 = ['hampter',' bird', 'monkey', 'banana', 'cat']

for j in listEx2:
    for pos, i in enumerate(listEx):
        if j in i:
            print j, "found in", i, "at position", pos, "of listEx"

This will print

cat found in cat *(select: "Brown")* at position 0 of listEx

answered Nov 13, 2011 at 21:55

Tim Pietzcker

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1 Comment

Paul Over a year ago

Why am I always so slow? :( - Whatever, your solution is good and works.

Mark Byers · Accepted Answer · 2011-11-13 22:07:06Z

3

Your problem is that you wrote j instead of i in the last line:

for j in listEx2:
    for i in listEx:
        if j in i:
            print listEx.index(i)
#                              ^ here

However, a better approach is to use enumerate:

for item2 in listEx2:
    for i, item in enumerate(listEx):
        if item2 in item:
            print i

edited Nov 13, 2011 at 22:07

answered Nov 13, 2011 at 21:50

Mark Byers

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2 Comments

poke Over a year ago

Please don’t just catch any exception, but only look for ValueError. – edit: Thanks xD

phales15 Over a year ago

I want to find the index of 'cat (select: "Brown")'.

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