In c# you can do ?? to check for null and then use a value like so..
DateTime? today = null;
DateTime todayNotNull = today ?? Date.Now;
Is there a shorthand way to do this in PHP?
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3 Answers
Yes.
$var = ConditionalTest ? ValueIfTrue : ValueIfFalse;
Note that both ValueIfTrue and ValueIfFalse must be used.
In your specific case:
<?php
$today = null;
$todayNotNull = isset($today) ? $today : date();
?>
Comments
You can use the Ternary operator as indicated by other users.
$today = null;
$todayNotNull = $today ? $today : time();
As of PHP 5.3, you can also shorten this to the familiar syntax you want:
$todayNotNull = $today ?: time();
Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, and expr3 otherwise.
Comments
$todayNotNull = ($today===NULL ? date() : $today);
UPDATE: Be careful when using implicit NULL check like $today ? $today : date().
true is true. (type: boolean)
false is false. (type: boolean)
null is false. (type: NULL)
[] is false. (type: array)
[0] is true. (type: array)
[1, 2, 3] is true. (type: array)
{1: 2, "x": 3} is true. (type: array)
"" is false. (type: string)
"0" is false. (type: string)
"1" is true. (type: string)
"2" is true. (type: string)
"x" is true. (type: string)
0 is false. (type: integer)
1 is true. (type: integer)
2 is true. (type: integer)
0 is false. (type: double)
0.1 is true. (type: double)
0.2 is true. (type: double)
I rather urge you to explicitly test for NULL.
