How can I make array in existing array's index without using pointer for e.g
float[] currentNode = new float[12]
float[] neighbour = new float[12]
neighbour[8] = new float[12]
neighbour[8] = currentNode;
and can access with neighbour[8][1]
other option is something using pointers.
float *pointer;
int []array = new int[12];
pointer = &array[0];
neighbour[8] = pointer
so does first solution possible w/o changing my both arrays ? any other solutions ?? .
You are looking for Multidimensional arrays.
int[,] myArray;
myArray = new int[,] {{1,2}, {3,4}, {5,6}, {7,8}}; // OK
You can't do that.
You have an array of float values, not an array of arrays.
Which means you cannot assign one element in the array (which holds a float value) a value which is an array.
You'd have to redefine your variables as:
float[][] neighbour = new float[12][];
This will declare an array of arrays, which means each element of the neighbour array can hold arrays of different lengths, or no array (null-reference).
If you want to declare a matrix, you can do it like this:
float[,] neighbour = new float[12, 8];
You also could use generics:
List<List<float>> numbers = new List<List<float>>();
numbers.Add(new List<float>());
numbers.Add(new List<float>());
numbers[0].Add(2.3);
numbers[0].Add(5);
numbers[0].Add(8.74);
numbers[1].Add(6.8);
numbers[1].Add(9.87);
float aNumber = numbers[1][0]; //6.8
float anotherNumber = numbers[0][2]; //8.74
