When you define a bash function you can call bash commands with command command.
function ls() {
clear
command ls "$@"
}
How would you pipe commands in bash function?
e.g.
function ls() {
clear
command ls "$@" | head
}
EDIT: The output would be OK, but there is --color=auto. Look here
Try this in your ~/.bashrc
function ls() { clear ; builtin ls "$@" | head ; }
It's similar to the function you have already but with the inclusion of builtin, it guarantees not to get stuck in a loop calling itself. Hope this works!
EDIT: It should be noted that any colour information produced by ls with the --color=auto option won't be carried through the pipe to head.
You can pipe the colour information generated by the ls command to head if you run ls in a so-called pseudo terminal (so that ls thinks it is writing its output to a terminal, and not a pipe). This can be achieved by using the script command.
ls() {
type -P command 1>/dev/null ||
{ echo 'No "command" executable found!'; return 1; }
clear
script -q /dev/null command ls -G "$@" | tr -d '\r' | head
}
cat /usr/bin/command # on Mac OS X 10.6.8
#!/bin/sh
# $FreeBSD: src/usr.bin/alias/generic.sh,v 1.2 2005/10/24 22:32:19 cperciva Exp $
# This file is in the public domain.
builtin `echo ${0##*/} | tr \[:upper:] \[:lower:]` ${1+"$@"}
For more information see: ls command operating differently depending on recipient
clear; ls | head, but I want function, not aliasls?