Variable between php and Javascript

Question

code:

<?php

    mysql_connect("localhost", "bikemap", "pedalhard") or die(mysql_error()); 
    mysql_select_db("test") or die(mysql_error()); 
    $data = mysql_query("SELECT * FROM gpsdata");     
    $aData = array();
    while($row = mysql_fetch_assoc($data))
        $aData[$row['idgpsdata']] = array($row);
        $json = json_encode($aData);
?>

    var json = "<?php echo $json; ?>";
    document.write(json.length);
    alert('half done');

    for(var x=0; x < json.length; x++) {
        document.write("<li>"+ x + " " + json[x]+ "</li>");
    }

Output of the code:

20

0 <
1 ?
2 p
3 h
4 p
5
6 e
7 c
8 h
9 o
10
11 $
12 j
13 s
14 o
15 n
16 ;
17
18 ?
19 >

if you take out the line numbers is: "<?php echo $json; ?>"

Looks suspiciously like a line where I'm trying to transfer the php variable $json to javascript variable json.

I've tried every type of bracketry and quote to get this to work. Anyone see any mistakes or have any suggestions?

Are you sure that the PHP code is being executed? That is, are you requesting the page from a web server with PHP enabled or are you just opening the page from the file system in the browser? — Vincent Ramdhanie
– Vincent Ramdhanie, Commented Nov 16, 2011 at 4:41
@VincentRamdhanie I am running the code from a site hosted with PHP enabled. — Loren Zimmer
– Loren Zimmer, Commented Nov 16, 2011 at 4:43
@LorenZimmer, why don't you "view source" on the output of your script and show us that. — Brad
– Brad, Commented Nov 16, 2011 at 4:44
@Brad this kind of development is new to me where would I "view source" from? — Loren Zimmer
– Loren Zimmer, Commented Nov 16, 2011 at 4:51

Naypa · Accepted Answer · 2011-11-16 11:00:46Z

1

Try

var json = {<?php echo $json; ?>};

or maybe

var json = eval("{<?php echo $json; ?>}");

Be sure your code is interpreted as php by the server. The file extension '.js' is usually not configured in this way.

If you want to embed your php file as a js, you'd better to rename it as .php and add the required header like that :

<?php
header("Content-type","text/javascript");
?>

var json = {<?php echo $json; ?>};

answered Nov 16, 2011 at 11:00

Naypa

1726 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Loren Zimmer Over a year ago

I needed just the php file to pass the variables

James Anderson · Accepted Answer · 2011-11-16 05:10:33Z

0

You could try:-

var json = <? echo $json ?>;

You cannot execute php code inside the Javascript. Instead you must get php to write the relevent javascript code;

answered Nov 16, 2011 at 5:10

James Anderson

27.5k7 gold badges55 silver badges81 bronze badges

Comments

Arfeen · Accepted Answer · 2011-11-16 05:44:52Z

0

You could do it other way, that is, put your javascript inside php:

echo "<script>
var json = $json; 
document.write(json.length);
alert('half done');

for(var x=0; x < json.length; x++) {
    document.write(\"<li>\"+ x + \" \" + json[x]+ \"</li>\");
}
</script>";

answered Nov 16, 2011 at 5:44

Arfeen

2,6235 gold badges30 silver badges49 bronze badges

Collectives™ on Stack Overflow

Variable between php and Javascript

3 Answers 3

1 Comment

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

1 Comment

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related