I need a regex that matches the alphanumeric patterns except totally numeric ones.
asdfgesod valid 1asdndwdd valid asd124asd valid a2asd43bd valid 123346678 invalid
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4 Answers
/^[a-z0-9]*[a-z][a-z0-9]*$/i
Broken down:
^[a-z0-9]* - String starts with any number (including zero) of alphanumeric characters
[a-z] - String has an a-z character
[a-z0-9]*$ - String ends with any number (including zero) of alphanumeric characters
4 Comments
Paul
As you can see the first four match and the fifth doesn't as intended: codepad.viper-7.com/HiTFio
tuze
I feel silly when the answer is that easy. I tried lot of ridiculous things. Thank you so much. You saved me from endless headaches.
Paul
@tuze You're welcome. Also don't include the
i at the end if you don't want (uppercase) A-Z to be considered alpha characters.tuze
Thanks. I know how to use modifiers.
A solution would be to first check if the string contains only digits, if not check rest of the string. The following regex would do that:
^(?![\d]+$)[a-z0-9]+$
See it in action here: http://regexr.com?2v8n5
Comments
Use in case of java StringUtils.isNumeric(String value) check if string contains only numbers.
BTW: if string matches regex: "^\d*$" this means that it contains only digits.
