$js in select dropdown in codeigniter

Question

I have a js in a folder js. I call the file in the header.
I have the next code in my view:

<?php echo form_dropdown('mydropdown',$options) ?>

I need to pass the paramether $js, could you help me with the syntax?

$js = 'id="shirts" onChange="display(this,\'id1\',\'id2\');"';


<?php echo form_dropdown('mydropdown',$options, $js) ?>

When I see the source code of my dropdown I can't see the id="shirts", then I believe that the function javascript is not recognized.

What's my error. My codeigniter version is 2.0.

Thanks.

$js needs to be the 4th parameter. It's form_dropdown('name', $options, 'selected', $js); — gen_Eric
– gen_Eric, Commented Nov 21, 2011 at 16:33

xiidea · Accepted Answer · 2014-03-29 03:39:04Z

1

javascript should be the fourth parameter to this call. So add a null parameter in the third (which is for the selected value of the dropdown):

<?php echo form_dropdown('mydropdown',$options, null, $js) ?>

xiidea

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answered Nov 21, 2011 at 16:33

swatkins

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