php if statement in echo

Question

I've been struggling with this from yesterday. I'm trying to do an if statement in an echo, I've followed this post (if block inside echo statement?) but my if statement does not evaluate to true. I've even put in the values for $quenr1 & $anscho1 but no sucess. Please help. Please reply if you need all the code.

$quenr1 = 1;
$anscho1 = 'A';
if ($q_type != 'mr') 
{
    if($option1!="") 
    {
        echo "<input type='radio' name='$quenr1' value='A'" . ($anscho1 == A ? 'checked="checked"' : '') . ">$quenr1<br />";
    }
}

EDITED

Thanks for all the replies, you've put me in the right direction. As a last resort I removed all my code and started from scratch and just put in the query to retrieve the data and display the form and it worked fine.

You're missing the closing brackets and you're missing layout. — markus
– markus, Commented Nov 22, 2011 at 9:38
instead of trying to write all your code in a single line , you should try to reduce the cyclomatic complexity. — tereško
– tereško, Commented Nov 22, 2011 at 9:41
I suggest developing with error display on (or checking your error log), and error reporting setting to E_ALL. I'm assuming the A is not actually a constant but rather a literal missing quotes. Error reporting will tell you that. — Corbin
– Corbin, Commented Nov 22, 2011 at 9:45

zuloo · Accepted Answer · 2011-11-22 17:34:43Z

4

     echo "<input type='radio' name='$quenr1' value='A'".(($anscho1 == 'A')? ' checked="checked"' : '').">$quenr1<BR>";

right put () arround your condition and '' around the A

edited Nov 22, 2011 at 17:34

answered Nov 22, 2011 at 9:35

zuloo

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3 Comments

kapa Over a year ago

Actually both answers are missing a space (between value and checked).

Wilest Over a year ago

@bazmegakapa I've changed it to this but still no luck. echo "<input type='radio' name='$quenr1' value='A'".(($anscho1 == 'A')? 'checked="checked"' : '').">$quenr1<BR>";

kapa Over a year ago

@wilest Try it like this: ' checked="checked"'

Jake N · Accepted Answer · 2011-11-22 09:43:07Z

4

Try this

echo "<input type='radio' name='$quenr1' value='A'" .
  (($anscho1 == 'A') ? 'checked="checked"' : '')
  . ">$quenr1<BR>";

Put () around your condition.

edited Nov 22, 2011 at 9:43

answered Nov 22, 2011 at 9:34

Jake N

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13 Comments

Dan Hanly Over a year ago

Essentially the same answer as the other guy, but this is easier to read!

Jake N Over a year ago

Yeah, line breaks always help

psycho Over a year ago

Not a solution here. For such a simple condition, () are not mandatory, just a little better for visibility. '' around litteral value, though, are.

kapa Over a year ago

@psycho It is not mandatory, but it matters. (Check this)[codepad.org/IcXA12zY].

psycho Over a year ago

@wilest Instead of comments, consider using 'edit' function with new informations about your problem. jakenoble's answer is (now) right, so if it doesn't work, you probably forgot / misunderstood something or made a typo.

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