Javascript: Concat an array while maintaining objects

Question

I have two arrays:

ArrayOne = new Array(Array1, Array2);
ArrayTwo = new Array(Array3, Array4);
ArrayThree = new Array();

I want to do:

ArrayThree = ArrayOne.concat(ArrayTwo);

With the result:

ArrayThree = {ArrayOne, ArrayTwo}

However this operation results in:

ArrayThree = {ArrayOne[0], ArrayOne[1]... ArrayOne[n], ArrayTwo[0], ArrayTwo[1]... ArrayTwo[n]};

Any advice on how to get {ArrayOne, ArrayTwo} so the original array object is maintained?

Thanks

Backticks (`) are for inline code. To format a block of lines as code, indent them an extra four spaces. The "{}" button in the editor toolbar does this for you. Edit your question and try it out. Click the orange question mark in the editor toolbar for more information and tips on formatting. — outis
– outis, Commented Nov 29, 2011 at 8:22

Thilo · Accepted Answer · 2011-11-29 08:18:49Z

1

var ArrayThree = [ ArrayOne, ArrayTwo ];

answered Nov 29, 2011 at 8:18

Thilo

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Comments

Abdul Munim · Accepted Answer · 2011-11-29 08:39:04Z

1

If you can't use concat function...

var ArrayThree = [ArrayOne, ArrayTwo];

or even,

var ArrayThree = new Array(ArrayOne, ArrayTwo);

not a problem if you have ArrayThree previously initialized

answered Nov 29, 2011 at 8:39

Abdul Munim

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3 Comments

Thilo Over a year ago

I think it is because new Array is discouraged. But it is not strictly wrong, is it? And the preferred version is also mentioned.

Abdul Munim Over a year ago

I didn't know that it's discouraged. Yeah probably because of that

rossipedia Over a year ago

Downvoted because I believe this answer originally suggested use of the concat method, which is exactly what the OP didn't want. If I am mistaken, my apologies.

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