I want execute JavaScript function which the name is coming as a string dynamically. I don't need to pass any parameters while executing the function.
Please can any one guide me how to achieve this?
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eval is evil, try to avoid it at all costsuser1046334– user10463342011-12-01 15:29:52 +00:00Commented Dec 1, 2011 at 15:29
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Check this threads stackoverflow.com/questions/676721/… and stackoverflow.com/questions/5618007/…dku.rajkumar– dku.rajkumar2011-12-01 15:33:17 +00:00Commented Dec 1, 2011 at 15:33
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7 Answers
one simple way
eval("SomeFunction()");
or
var funcName = "SomeFunction";
var func == window[funcName];
func();
Comments
dangerous but you could use eval(method_name+"()")
Comments
are you talking about ´eval()´??
var foo = "alert('bar')";
eval(foo);
Hope this helps;
Comments
function a() {
console.log('yeah!');
}
var funcName = 'a'; // get function name
this[funcName]();
Comments
If the function is global, you should do window[funcName]() in browser.
2 Comments
kamesh
window[funcName]() it is working in Firefox but not working in IE8 Iam getting error in IE8 is expected identifier
Using eval is the worst way imaginable. Avoid that at all costs.
You can use window[functionname]() like this:
function myfunction() {
alert('test');
}
var functionname = 'myfunction';
window[functionname]();
This way you can optionally add arguments as well
Comments
Perhaps a safer way is to do something like this (pseudo code only here):
function executer(functionName)
{
if (functionName === "blammo")
{
blammo();
}
else if (functionName === "kapow")
{
kapow();
}
else // unrecognized function name
{
// do something.
}
You might use a switch statement for this (it seems like a better construct):
switch (functionName)
{
case "blammo":
blammo();
break;
case "kapow":
kapow();
break;
default:
// unrecognized function name.
}
You can optimize this by creating an array of function names, searching the array for the desired function name, then executing the value in the array.
