conditional display php and mysql

Question

<?php echo $row['time']; ?>&nbsp;Normal time (<?php echo $row['time']/2; ?> years)

I want to have a case when ['time']/2 > 1 it is shown as years but if it is 1 it shall be shown only as year

How can I do this using if else

any idea?

Jason Brumwell · Accepted Answer · 2011-12-01 20:42:34Z

1

<?php $years = $row['time']/2; ?>
<?php echo $row['time']; ?>&nbsp;Semster (<?php echo $years > 1 ? $years.' years' : $years.' year'; ?>)

answered Dec 1, 2011 at 20:42

Jason Brumwell

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Comments

Jemaclus · Accepted Answer · 2012-03-13 19:38:28Z

0

You only want to show "year" if $row['time']/2 is 1 (0 is still plural), so you want to do something like:

   <? $years = $row['time'] / 2; ?>
   <?= $row['time'] ?> Semester (<?= $years == 1 ? '1 year' : $years.' years' ?>)

Good luck. :)

answered Dec 1, 2011 at 20:50

Jemaclus

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Galen · Accepted Answer · 2011-12-01 20:43:38Z

0

<?php echo $row['time']; ?>&nbsp;Semster (<?php echo $row['time']/2; ?> year<?php if( $row['time']/2 > 1 ): ?>s<?php endif; ?>)

Leave off the s and only add it if time/2 > 1

answered Dec 1, 2011 at 20:43

Galen

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