How to count order number of values in an array?

Question

I have an array with a few values and want to do something like this:

 $arrayvalues = array_reverse(explode(', ', somefunction()));
 foreach ( $arrayvalues as $arrayvalue ) :
           printf('<li class="'.$countvalue.'">'.$arrayvalue.'</li>');  
 endforeach;

I want to have in $countvalue the number of the value in the array

ie... the array will be something like this: ("apple", "orange", "grapefruit")

I want the number to match the order number of these values apple = 1, orange = 2, grapefruit = 3

or actually even if it's just an incremental number according to the values echoed it doesn't matter, I just need to insert a css class represented by an incremembtal number

I tried playing $i... count... but I don't know how to achieve what I want; I'm more a designer than a coder, I looked in the PHP help but couldn't find a clear solution for my case

thank you

Community · Accepted Answer · 2017-05-23 12:20:12Z

4

You already have an incremental number based on order. Keep in mind, this only works if your key's are 0-based. If you use an associative array you will need to use a for loop instead (as suggested by nickb).

$arrayvalues = array_reverse(explode(', ', somefunction()));
foreach ( $arrayvalues as $key => $arrayvalue ){
    echo "<li class='$key'>$arrayvalue</li>";
}

edited May 23, 2017 at 12:20

CommunityBot

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answered Dec 1, 2011 at 20:57

vascowhite

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2 Comments

Abhi Beckert Over a year ago

This is what you should do. All the other answers so far are unnecessarily complicated, and complex code leads to buggy code. @LeviMorrison no he doesn't: "actually even if it's just an incremental number according to the values echoed it doesn't matter". The $key value is guaranteed to be unique.

Levi Morrison Over a year ago

@AbhiBeckert Noted. Also, printf is useless here. I'd suggest echo "<li class='$key'>$arrayvalue</li>"; There's no point not to.

Polynomial · Accepted Answer · 2011-12-01 21:02:08Z

1

 $arrayvalues = array_reverse(explode(', ', somefunction()));
 $i = 0;
 foreach ( $arrayvalues as $arrayvalue )
 {
           $i++;
           printf('<li class="'.$i.'">'.$arrayvalue.'</li>');
 }

edited Dec 1, 2011 at 21:02

answered Dec 1, 2011 at 20:54

Polynomial

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10 Comments

Leysam Rosario Over a year ago

regarding to Fulvio question your $i++; needs to be before printf('<li class="'.$i.'">'.$arrayvalue.'</li>');

("apple", "orange", "grapefruit") I want the number to match the order number of these values apple = 1, orange = 2, grapefruit = 3

Levi Morrison Over a year ago

-1: I'm not going to advocate mixing foreach and a manual counter when his array is not associate.

Polynomial Over a year ago

@LeviMorrison - It's clean, works, and isn't a performance detriment. Sure, you can use a for loop, but you're just replacing $arrayvalue with $arrayvalues[$i]. I think this method is more intuitive.

Polynomial Over a year ago

@LeviMorrison - Relax. There's no need to get so stressed out about (what you consider to be) a slightly imperfect answer.

Polynomial Over a year ago

@narcisradu - I just copypasted the OP's code and modified it as little as possible so he'd understand it easily.

|

Levi Morrison · Accepted Answer · 2011-12-01 21:09:05Z

0

Use a for loop to iterate over your array, like so:

 for( $i = 0, $j = count( $arrayvalues); $i < $j; $i++) :
           printf('<li class="' . ($i + 1) . '">' . $arrayvalues[$i] . '</li>');
 endfor;

If you want the index $i to start at one, you need to add one in the printf statement.

Side note: You don't need printf here if you're not actually generating formatted output.

edited Dec 1, 2011 at 21:09

Levi Morrison

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answered Dec 1, 2011 at 20:53

nickb

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3 Comments

Levi Morrison Over a year ago

Syntax error: endforeach => endfor I should -1 you for not testing the code you supply as an answer.

Narcis Radu Over a year ago

+1 for initializing $j and not counting the array in every step of the loop as most of coders those days

nickb Over a year ago

@LeviMorrison A -1 for that?! That's not nice... ;)

Leysam Rosario · Accepted Answer · 2011-12-01 21:21:56Z

0

 $arrayvalues = array_reverse(explode(', ', somefunction()));
 $i=0;
 foreach ( $arrayvalues as $arrayvalue ) :
           ++$i;
           $countvalue = $i;
           printf('<li class="'.$countvalue.'">'.$arrayvalue.'</li>');  
 endforeach;

We (or I) advise you use a normal for loop.

for($i = 0; $i < count($arrayvalues); $i++) {
     printf('<li class="'.($i+1).'">'.$arrayvalue.'</li>');  
}

edited Dec 1, 2011 at 21:21

answered Dec 1, 2011 at 20:55

Leysam Rosario

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