Django model object initialization

Question

If I do

obj = Object()
obj.att1 = 'test'
obj.att2 = 'test'
obj.save()

obj.id --> works fine

But if I do

obj=Object(att1='test',att2='test').save()

Doing obj.id --> obj seems to be Nonetype at this stage

Is this the case?

David H. Clements · Accepted Answer · 2011-12-02 07:13:32Z

8

I don't know the exact framework you are using, but I am going to take a guess as to the problem:

Object(att1='test',att2='test').save()

The save() function doesn't appear to return the Object instance, it returns None. So you would normally:

obj=Object(att1='test',att2='test')
obj.save()

Then check obj.id.

answered Dec 2, 2011 at 7:13

David H. Clements

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3 Comments

user1076881 Over a year ago

Thanks dclements. Your method works fine. Im using python language in Django framework by the way.

Daniel Roseman Over a year ago

A Django one-liner that creates, saves, and returns the object is Object.objects.create(att1='test', att2='test').

Ignas Butėnas Over a year ago

This is perfect answer. Because what you are doing is just two different things. In the first case you creating the object and obj is OBJECT. The second case - the obj is the result of the FUNCTION.

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