Class.method = function () { this.xx }
Class.prototype.method = function () { this.xx }
var clazz = new Class();
clazz.method();
When I call the 4th line this in the function will refer to clazz
But when Class.method() is executed, what will this refer to?
this within the Class.prototype.method function will still refer to the Class instance. This isn't a static method, a static (i.e. one per class) method would be something like:
Class.method = function () {
// I am a static method
};
For example:
var Example = function () {
this.name = "DefaultName";
};
Example.prototype.setName = function (name) {
this.name = name;
}
var test = new Example();
test.setName("foo");
console.log(test.name); // "foo"
If you call .method() on your constructor function itself (without new), this will still be bound to the Class object. The this value always depends on the type of invocation, since you are calling the function from within an object (= a method), this will be bound to that context.
Class = function() {
this.xx = "hello";
}
Class.method = function () { this.xx }
Class.prototype.method = function () { alert(this.xx) }
var clazz=new Class();
clazz.method(); // display "hello";
Class.method() // undefined
it will refer to the object calling the Class.method function.
