How would I make my server run a php script by triggering it manually using php? Basically I have a pretty big cronjob file that is ran every 2 hours, but I want to be able to trigger the file manually myself without having to wait for it to load (i want it to be done on the server's side).
EDIT: I want to execute the file from a php file... Not command line.
You can invoke a PHP script manually from the command line
hello.php
<?php
echo 'hello world!';
?>
Command line:
php hello.php
Output:
hello world!
See the documentation: http://php.net/manual/en/features.commandline.php
EDIT OP edited the question to add a critical detail: the script is to be executed by another script.
There are a couple of approaches. First and easiest, you could simply include the file. When you include a file, the code within is "executed" (actually, interpreted). Any code that is not within a function or class body will be processed immediately. Take a look at the documentation for include (docs) and/or require (docs) (note: include_once and require_once are related, but different in an important way. Check out the documents to understand the difference) Your code would look like this:
include('hello.php');
/* output
hello world!
*/
Second and slightly more complex is to use shell_exec (docs). With shell_exec, you will call the php binary and pass the desired script as the argument. Your code would look like this:
$output = shell_exec('php hello.php');
echo "<pre>$output</pre>";
/* output
hello world!
*/
Finally, and most complex, you could use the CURL library to call the file as though it were requested via a browser. Check out the CURL library documentation here: https://www.php.net/manual/en/ref.curl.php
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://www.myDomain.com/hello.php");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true)
$output = curl_exec($ch);
curl_close($ch);
echo "<pre>$output</pre>";
/* output
hello world!
*/
Documentation for functions used
include: https://www.php.net/manual/en/function.include.phprequire: https://www.php.net/manual/en/function.require.phpshell_exec: https://www.php.net/manual/en/function.shell-exec.phpcurl_init: https://www.php.net/manual/en/function.curl-init.phpcurl_setopt: https://www.php.net/manual/en/function.curl-setopt.phpcurl_exec: https://www.php.net/manual/en/function.curl-exec.phpcurl_close: https://www.php.net/manual/en/function.curl-close.php
include/require will run it in the original script’s environment. That means with all its globals, ini settings etc. Running as a shell script or through a HTTP request ensures that the other script runs safely in its own separate environment without interfering with the original one’s.
localhost or if you otherwise take measures to prevent access by unauthorized parties. That could be .htaccess, tokens in the URL, session, cookies, web server configuration, etc. It's hard to guess what you mean.you can use the backtick notation:
`php file.php`;
You can also put this at the top of the php file to indicate the interpreter:
#!/usr/bin/php
Change it to where you put php. Then give execute permission on the file and you can call the file without specifying php:
`./file.php`
If you want to capture the output of the script:
$output = `./file.php`;
echo $output;
$output = `php file.php` should work as wellThe OP refined his question to how a php script is called from a script. The php statement 'require' is good for dependancy as the script will stop if required script is not found.
#!/usr/bin/php
<?
require '/relative/path/to/someotherscript.php';
/* The above script runs as though executed from within this one. */
printf ("Hello world!\n");
?>
<?php
$output = file_get_contents('http://host/path/another.php?param=value ');
echo $output;
?>
If it is a linux box you would run something like:
php /folder/script.php
On Windows, you would need to make sure your php.exe file is part of your PATH, and do a similar approach to the file you want to run:
php C:\folder\script.php
Open ssh and execute the command manually?
php /path/to/your/file.php
On the command line:
> php yourfile.php
I think the function "eval" is the right solution.
Official docs here: https://www.php.net/manual/en/function.eval.php
And the code should be of the following form:
$some_code = retrieve_or_generate_some_php_code();
eval($some_code);
Possible and easiest one-line solution is to use:
file_get_contents("YOUR_REQUESTED_FILE");
Or equivavelt for example CURL.
Try this:
header('location: xyz.php'); //thats all for redirecting to another php file
I think this is what you are looking for
<?php include ('Scripts/Php/connection.php');
//The connection.php script is executed inside the current file ?>
The script file can also be in a .txt format, it should still work, it does for me
e.g.
<?php include ('Scripts/Php/connection.txt');
//The connection.txt script is executed inside the current file ?>
php file.php?