CSS & PHP; Add URL inside

Question

<?php $picNumberSlide = "<div id='slidenumber'></div>" ;?>

Num Print

<div id="slidenumber"></div> -> (Picture slide number)

Link

<a href="share?picNum=<?php echo $picNumberSlide;?>">

Not work.

<div id='slidenumber'></div> slide number of the screen writes. I intended to write inside the URL's

How i can do? Thank you! (i sorry for Eng)

Scott · Accepted Answer · 2011-12-13 12:11:09Z

1

<?php $picNumberSlide = "<div id='slidenumber'></div>" ;?>

The above defines the $picNumberSlide variable as a div.

<a href="share?picNum=<?php echo $picNumberSlide;">

Here you are placing a div inside the href of an anchor, that will never work.

You need to assign the $picNumberSlide variable only the number you wish to use.

Then using

<a href="share?picNum=<?php echo $picNumberSlide; ?>">

will work.

$picNumberSlide should only = a number

edited Dec 13, 2011 at 12:11

answered Dec 13, 2011 at 12:04

Scott

21.9k8 gold badges45 silver badges57 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

You forgot to close the php tag.

True. Edited. I was just copy/pasting.

Thank you! Results (written in screen); <a href="share?picNum=<div id='slidenumber'></div>" The required number but the text is written.

cowls · Accepted Answer · 2011-12-13 12:03:06Z

0

Change <a href="share?picNum=<?php echo $picNumberSlide;">

To <a href="share?picNum=<?php echo $picNumberSlide;?>">

(You were missing the closing tag for php)

answered Dec 13, 2011 at 12:03

cowls

24.4k9 gold badges51 silver badges78 bronze badges