How can I use proper object-oriented models in CodeIgniter with constructors?

Question

The way I create CodeIgniter models at the moment is (i.e. no constructor, having to pass userID all the time and limited to one object):

$this->load->model('User');
$this->user->set_password($userID, $password);

But I would like to do it like this:

$this->load->model('User');
$User = new User($userID);
$User->set_password($password);

UPDATE: Perhaps just a user model was a poor example.

For instance, if I have a shopping list that has various items I would like to use PHP in this way:

$this->load->model('List');
$this->load->model('Item');

$List = new List();
$items[] = new Item($itemName1, $itemPrice1);
$items[] = new Item($itemName2, $itemPrice2);

$List->add_items($items);

CodeIgniter feels fundamentally broken in handling PHP OO in this way. Does anyone have any solutions that can still use the superobject within every model?

Codeigniter use one big superobject called CI. I don't think be a good idea add new objects to that framework. In any case they should be inherit from him. — Igor Parra
– Igor Parra, Commented Dec 13, 2011 at 18:49
You are not supposed to use the load-> function for every instance of every object in CI. It's only for application-level items. Nothing prevents you from creating your own object (library or model) and using require_once to make them available, then instantiating/using them however you wish. If you need access to the CI object, you can get it from anywhere by doing $CI =& get_instance(); — minboost
– minboost, Commented Dec 14, 2011 at 1:17

minboost · Accepted Answer · 2011-12-13 18:43:07Z

13

You can do it like you normally would:

require_once(APPPATH.'models/User.php');
$User = new User($userID);

Or, you can rely on a table-level model to return a record-level model:

$this->load->model('users_model'); // users (plural) is the table-level model
$User = $this->users_model->get_user($userID);

Meanwhile, in users_model

require_once(APPPATH.'models/User.php');

public function get_user($userID)
{
  // get a record from the db
  // map record to model
  // return model
}

answered Dec 13, 2011 at 18:43

minboost

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Harsh · Accepted Answer · 2011-12-13 18:46:07Z

0

you can subclass the model or just add something in the constructor I think you need to adjust code to do it the way you're looking to…

answered Dec 13, 2011 at 18:46

Harsh

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