I have a list, that looks like this in python:
ex = ['(1..3),(5..8)']
I need to get out the list like this:
[(1, 3), (5, 8)]
I tried using the replace function, but could only get like
['(1, 3), (5,8)'] and could not lose the ' marks.
Hope someone can help me.
Thanks
import ast
ex = ['(1..3),(5..8)']
list(ast.literal_eval(ex[0].replace('..', ',')))
# returns [(1, 3), (5, 8)]
ast.literal_eval is safe. eval is not.
For your updated question:
ex2 = ['(2..5)', '(7..10)']
[ast.literal_eval(a.replace('..', ',')) for a in ex2]
# returns [(2, 5), (7, 10)]
[(2, 5), (7, 10)] is a list of tuples of integers. You can access its elements: result[0][1] == 2. Just start ipython, paste the lines into it and try yourself.Look like some regex task.
>>> import re
>>> ex = ['(1..3),(5..8)']
>>> re.findall(r'\((\d+)\.\.(\d+)\)', ex[0])
[('1', '3'), ('5', '8')]
>>> # if you want tuple of numbers
... [tuple(map(int, x)) for x in _]
[(1, 3), (5, 8)]
(1..3) xxx (5..8) 12, 3 is accepted even though it does not have the right format).This became uglier than I expected:
In [26]: ex = ['(1..22),(3..44)']
In [27]: [tuple([int(i) for i in s.strip('()').split('..')])
for s in ex[0].split(',')]
Out[27]: [(1, 22), (3, 44)]
if your format is constant, this should work :
>>> n = list(eval(ex[0].replace("..",",")))
>>> n
[(1, 3), (5, 8)]
UPDATE : using literal eval ( safer ):
import ast
result = list(ast.literal_eval(ex[0].replace("..",",")))
eval a string that a user can manipulate in any way. You can do safe eval using ast.literal_eval(). Edit: @Doboy: Beat me to it!
eval.