python regexp parse

Question

I have hash:

{'login': u'myemail ([email protected])'}

I need parse only email [email protected]

What regexp I must compose

Michael Berkowski · Accepted Answer · 2011-12-16 15:35:14Z

2

No regex is needed. Use string manipulation instead. This will split the value on the first space, then strip the () from the second item ([1]) of the returned array.

yourhash = {'login': u'myemail ([email protected])'}

email = yourhash['login'].split()[1].strip("()")

print(email)
# [email protected]

answered Dec 16, 2011 at 15:35

Michael Berkowski

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David K. Hess · Accepted Answer · 2011-12-16 15:40:57Z

2

If you really need a regular expression solution (versus the excellent string split options also posted) this will do it for you:

>>> import re
>>> re.match('.*\((.*)\)', 'myemail ([email protected])').group(1)
'[email protected]'
>>>

answered Dec 16, 2011 at 15:40

David K. Hess

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Wilduck · Accepted Answer · 2011-12-16 15:35:04Z

1

Use string methods instead:

my_dict['login'].split['('][1].strip(')')

answered Dec 16, 2011 at 15:35

Wilduck

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Brigand · Accepted Answer · 2011-12-16 15:38:16Z

1

There are many patterns for matching emails. A good resource can be found here.

For example,

^[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}$

answered Dec 16, 2011 at 15:38

Brigand

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