Converting between types in Haskell

Question

I'm trying to make a simple function to return a centered string of text in Haskell, but I'm having trouble just finding how much padding to insert either side. I have this:

center padLength string = round ((padLength - (length string)) / 2)

Which gives the following error:

No instance for (Fractional Int)
  arising from a use of '/'
Possible fix: add an instance declaration for (Fractional Int)
In the first argument of 'round', namely
  '((padLength - (length string)) / 2)'
In the expression: round ((padLength - (length string)) / 2)
In an equation for `center':
    center padLength string = round ((padLength - (length string)) / 2)

How can I (basically) convert from an Double (I think) to an Int?

ehird · Accepted Answer · 2011-12-18 21:03:18Z

9

The problem is not that you can't convert a Double to an Int — round accomplishes that just fine — it's that you're trying to do division on an Int (padLength - length string). The error message is just telling you that Int is not an instance of Fractional, the typeclass for numbers that can be divided.

In general, you could use fromIntegral (padLength - length string) to turn it into a Double, but in this case, you can simply use integer division directly:

center padLength string = padLength - (length string) `div` 2

a `div` b is just a nicer way of writing div a b; you can use any function as a binary operator like this.

edited Dec 18, 2011 at 21:03

answered Dec 18, 2011 at 20:54

ehird

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1 Comment

Dean Barnes Over a year ago

Why does it need the `? I'm a bit new to Haskell

JB. · Accepted Answer · 2011-12-18 20:56:35Z

1

You're trying to use fractional division / on operands of integral type, but that's not defined.

You should either convert the operands to Double before dividing (using fromIntegral), or use integral division div.

answered Dec 18, 2011 at 20:56

JB.

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