AWS .NET SDK Multipart File Upload from Http

Question

I've implemented a .ashx handler which receives chunked upload parts of a file from the client. Previously I first stored the files in a temp folder before uploading them to AWS. As the files have become quite big, I'd like to skip the temp folder part and upload them directly to AWS using the MultiPart requests.

It looks fine so far, but I can't find an overload which accepts either the HttpPostedFile or Stream for the upload..

I something like the following possible?

        // Create request to upload a part.
        UploadPartRequest uploadRequest = new UploadPartRequest()
            .WithBucketName(myBucket)
            .WithKey(myKey)
            .WithUploadId(myUploadId)                
            .WithPartNumber(partNumber)
            .WithInputStream(inputStream);

zirbel · Accepted Answer · 2012-11-27 14:45:23Z

2

UploadPartRequest uploadRequest = new UploadPartRequest()
        .WithBucketName(myBucket)
        .WithKey(myKey)
        .WithUploadId(myUploadId)                
        .WithPartNumber(partNumber)
        .WithInputStream(stream) as UploadPartRequest;

This is also possible.

answered Nov 27, 2012 at 14:45

zirbel

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Comments

Mohammad Fahmawi · Accepted Answer · 2011-12-22 09:18:30Z

1

WithInputStream will return s3 request instead of UploadPartRequest so just cast the return type to UploadPartRequest

// Create request to upload a part.
        UploadPartRequest uploadRequest = new UploadPartRequest()
            .WithBucketName(myBucket)
            .WithKey(myKey)
            .WithUploadId(myUploadId)                
            .WithPartNumber(partNumber);

uploadRequest = (UploadPartRequest)uploadRequest.WithInputStream(ftiObject.sourceStream);

this works for me

answered Dec 22, 2011 at 9:18

Mohammad Fahmawi

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Comments

AyKarsi · Accepted Answer · 2011-12-20 08:33:54Z

0

Simple: Just set the Input Stream via the Property:

            // Create request to upload a part.
            UploadPartRequest uploadRequest = new UploadPartRequest()
                .WithBucketName(myBucket)
                .WithKey(myKey)
                .WithUploadId(UploadId)
                .WithPartNumber(PartNumber)
                .WithPartSize(inputStream.Length)
                .WithFilePosition(FilePosition);

            uploadRequest.InputStream = inputStream;

answered Dec 20, 2011 at 8:33

AyKarsi

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