incorrect value in array

Question

i have this code, but i can't understand why var_dump($jobs[0][0]) return Some Director, but when i do value='.$jobs[$i][0].' i simply get the first word, in this case only "Some". The question is why ? The same occurs in the others inputs.

thanks

<form method="post" id="customForm" action="">
    <?php
    for ($i = 0; $i < count($jobs); $i++) {
        $u = $i+1;
        echo '
        <div class ="empregadores" id="input_'.$u.'" style="margin-bottom: 10px;">
            <input placeholder="Cargo" name="myformdata[role][]" type="text" value='.$jobs[$i][0].' > 
            <input placeholder="Empregador" name="myformdata[company][]" type="text" value='.$jobs[$i][1].' >
            <input placeholder="Função" name="myformdata[role_function][]" type="text" value='.$jobs[$i][2].' >
        </div>';
    }

    ?>
    </form>

var_dump($jobs);

array
  0 => 
    array
      0 => string 'Some Director'
      1 => string 'some company' 
      2 => string 'some text'

Michael Berkowski · Accepted Answer · 2011-12-21 02:48:41Z

1

You have not enclosed the values in double quotes inside the value= attributes. Add opening and closing quotes, as in: value="'.$jobs[$i][0].'"

    echo '
    <div class ="empregadores" id="input_'.$u.'" style="margin-bottom: 10px;">
        <input placeholder="Cargo" name="myformdata[role][]" type="text" value="'.$jobs[$i][0].'" > 
        <input placeholder="Empregador" name="myformdata[company][]" type="text" value="'.$jobs[$i][1].'" >
        <input placeholder="Função" name="myformdata[role_function][]" type="text" value="'.$jobs[$i][2].'" >
    </div>';

Without the quotes, the HTML looks like value=Some director. The value ends at the first whitespace if not enclosed in quotes.

answered Dec 21, 2011 at 2:48

Michael Berkowski

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Comments

ruakh · Accepted Answer · 2011-12-21 02:49:31Z

1

You need to wrap the HTML attribute in double-quotes. For example, change this:

... type="text" value='.$jobs[$i][0].' >

to this:

... type="text" value="'.$jobs[$i][0].'" >

answered Dec 21, 2011 at 2:49

ruakh

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